获取telnet连接到python套接字服务器的问题

Question

所以我开始研究一种物联网项目，而我遇到的第一个问题就是在设置基本服务器时遇到了麻烦。使用本指南进行一些初始测试，以下是使用的代码：

'''


   Simple socket server using threads
'''

import socket
import sys

HOST = ''   # Symbolic name, meaning all available interfaces
PORT = 8888 # Arbitrary non-privileged port

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print 'Socket created'

#Bind socket to local host and port
try:
    s.bind((HOST, PORT))
except socket.error as msg:
    print 'Bind failed. Error Code : ' + str(msg[0]) + ' Message ' + msg[1]
    sys.exit()

print 'Socket bind complete'

#Start listening on socket
s.listen(10)
print 'Socket now listening'

#now keep talking with the client
while 1:
    #wait to accept a connection - blocking call
    conn, addr = s.accept()
    print 'Connected with ' + addr[0] + ':' + str(addr[1])

s.close()

我可以设置服务器，它将侦听套接字，但是当我尝试连接telnet时，它会超时。由于我在大学的网络上，这可能是事情没有经历的原因吗？我记得在C一段时间做过这样的事情，它似乎有效......

Answer 1

代码有效，但不会从客户端发送/接收。以下适度更改使服务器将beer tasty发送给任何幸运客户端。

源

'''
Simple socket server using threads
'''

import socket
import sys

HOST = ''   # Symbolic name, meaning all available interfaces
PORT = 8888 # Arbitrary non-privileged port

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print 'Socket created'

#Bind socket to local host and port
try:
    s.bind((HOST, PORT))
except socket.error as msg:
    print 'Bind failed. Error Code : ' + str(msg[0]) + ' Message ' + msg[1]
    sys.exit()

print 'Socket bind complete'

#Start listening on socket
s.listen(10)
print 'Socket now listening'

#now keep talking with the client
while 1:
    #wait to accept a connection - blocking call
    conn, addr = s.accept()
    print 'Connected with ' + addr[0] + ':' + str(addr[1])
    conn.send('beer tasty\n')   # <==
    conn.close()
s.close()

在Linux中使用Netcat进行测试。 （Telnet也应该工作）

测试

$ echo beer | nc -q1 localhost 8888
Connected with 127.0.0.1:37484
beer tasty