Question

我有这个数组：

char alph[] ={'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','0','1','2','3','4','5','6','7','8','9','.',',',':','?','=','-','(',')','"','\'','/','%','@','!'};

可以使用'perc'这样的单词更改符号'％'吗？

感谢您的帮助！

Answer 1

鉴于alph的声明，每个元素都是单个char，而字符串"perc"由多个字符组成。但请注意，字符文字'perc'（带单引号）是有效的C代码，但其值通常无用;如果你试图将它打印出来，你就会用垃圾而不是单词＆＃34; perc＆＃34 ;.

如果您想在数组中使用"perc"，那么您需要将数组的类型更改为const char *alph[]，并将所有其他元素更改为使用双引号（即{ {1}}等。）

Answer 2

您正在做的是将{em>单 char替换为multicharacter literal，这取决于实现。它可能有效，如何存储这些值取决于编译器，所以如果你这样做：

char[] a = {'a, 'b', 'c'};
a[0] = '123';

和

printf("%c", a[0]);

不打算像您一样打印123。

Answer 3

不，你可能没有，但你可以用字母'p' ...

替换它

你拥有的是一个char大小的数组，包含50个元素，字符值为-128到127 你可以在char *的数组中存储类似的数据，它们是指向具有空终止C字符串的内存位置的指针。

Answer 4

正如其他人所指出的那样，你不能。

但是，如果您从alph

数组中更改char的定义

char alph[] ={'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','0','1','2','3','4','5','6','7','8','9','.',',',':','?','=','-','(',')','"','\'','/','%','@','!'};

指向char

的指针数组

char * alph[] ={"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z","0","1","2","3","4","5","6","7","8","9",".",",",":","?","=","-","(",")","\"","'","/","%","@","!"};

这是可行的。在后一种情况下，只需：

alph[<index of %>] = "perc";

C：char数组中的单词

4 个答案: