无法为使用typedef的块编写正确的语法

Question

我有Objective-C代码，我尝试转换为Swift但失败了。

typedef void (^ CDVAddressBookWorkerBlock)(
    ABAddressBookRef         addressBook,
    CDVAddressBookAccessError* error
    );

@interface CDVAddressBookHelper : NSObject
{}

- (void)createAddressBook:(CDVAddressBookWorkerBlock)workerBlock;
@end

这是Objective-C实现：

 CDVAddressBookHelper* abHelper = [[CDVAddressBookHelper alloc] init];
 [abHelper createAddressBook: 
       ^(ABAddressBookRef addrBook, CDVAddressBookAccessError* errorCode) 
        {
         /* ...*/
        }
 ];

如何在Swift中编写它？

来自文档：

{(parameters) -> (return type) in expression statements}

这是xCode提供的模板：

这就是我的尝试：

var abHelper:CDVAddressBookHelper = CDVAddressBookHelper()

abHelper.createAddressBook(
        {(addrBook:ABAddressBookRef, errCode:CDVAddressBookAccessError) in

           if  addrBook == nil  {

           }
        } )

错误：

 Type 'ABAddressBook!' does not conform to protocol 'AnyObject'`

[编辑]

问候：swift-closure-declaration-as-like-block-declaration帖子我试着写typealias：

typealias CDVAddressBookWorkerBlock = (addrBook:ABAddressBookRef, errCode:CDVAddressBookAccessError) -> ()

下一步是什么？

如何让它发挥作用？

谢谢，

Answer 1

查看docs有关如何使用Cocoa和Core Foundation的信息。

这应该有效：

abHelper.createAddressBook() {
    (addrBook:ABAddressBook?, errCode:CDVAddressBookAccessError!) in                

            if addrBook == nil  {

            }


    }