是否可以在可消耗列表视图的每一行中添加不同的子视图XML?
我使用自定义适配器创建了一个可消耗列表视图 但我想把它变成以下
可展开列表视图包含数据性别(男性和女性)
如果性别是男性,当我们点击时,子视图应显示男性菜单
如果性别是女性,当我们点击时,子视图应显示女性菜单
如何实现它?
这是我的适配器代码
package com.example.expandlist;
import java.util.ArrayList;
import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseExpandableListAdapter;
import android.widget.ImageView;
import android.widget.TextView;
public class ExpandListAdapter extends BaseExpandableListAdapter {
private Context context;
private ArrayList<Group> groups;
public ExpandListAdapter(Context context, ArrayList<Group> groups) {
this.context = context;
this.groups = groups;
}
@Override
public Object getChild(int groupPosition, int childPosition) {
ArrayList<Child> chList = groups.get(groupPosition).getItems();
return chList.get(childPosition);
}
@Override
public long getChildId(int groupPosition, int childPosition) {
return childPosition;
}
@Override
public View getChildView(int groupPosition, int childPosition,
boolean isLastChild, View convertView, ViewGroup parent) {
Child child = (Child) getChild(groupPosition, childPosition);
if (convertView == null) {
LayoutInflater infalInflater = (LayoutInflater) context
.getSystemService(context.LAYOUT_INFLATER_SERVICE);
convertView = infalInflater.inflate(R.layout.child_item, null);
}
TextView tv = (TextView) convertView.findViewById(R.id.country_name);
ImageView iv = (ImageView) convertView.findViewById(R.id.flag);
tv.setText(child.getName().toString());
iv.setImageResource(child.getImage());
return convertView;
}
@Override
public int getChildrenCount(int groupPosition) {
ArrayList<Child> chList = groups.get(groupPosition).getItems();
return chList.size();
}
@Override
public Object getGroup(int groupPosition) {
return groups.get(groupPosition);
}
@Override
public int getGroupCount() {
return groups.size();
}
@Override
public long getGroupId(int groupPosition) {
return groupPosition;
}
@Override
public View getGroupView(int groupPosition, boolean isExpanded,
View convertView, ViewGroup parent) {
Group group = (Group) getGroup(groupPosition);
if (convertView == null) {
LayoutInflater inf = (LayoutInflater) context
.getSystemService(context.LAYOUT_INFLATER_SERVICE);
convertView = inf.inflate(R.layout.group_item, null);
}
TextView tv = (TextView) convertView.findViewById(R.id.group_name);
tv.setText(group.getName());
return convertView;
}
@Override
public boolean hasStableIds() {
return true;
}
@Override
public boolean isChildSelectable(int groupPosition, int childPosition) {
return true;
}
}
答案 0 :(得分:2)
您需要在getChildView
方法中为男性和女性创建两种不同的XML布局:
public View getChildView(int groupPosition, int childPosition,
boolean isLastChild, View convertView, ViewGroup parent) {
Child child = (Child) getChild(groupPosition, childPosition);
if (child.getGender==MALE){
if (convertView == null) {
LayoutInflater infalInflater = (LayoutInflater) context
.getSystemService(context.LAYOUT_INFLATER_SERVICE);
convertView = infalInflater.inflate(R.layout.child_item_male, null);
}
TextView tv = (TextView) convertView.findViewById(R.id.country_name);
ImageView iv = (ImageView) convertView.findViewById(R.id.flag);
tv.setText(child.getName().toString());
iv.setImageResource(child.getImage());
}else{
if (convertView == null) {
LayoutInflater infalInflater = (LayoutInflater) context
.getSystemService(context.LAYOUT_INFLATER_SERVICE);
convertView = infalInflater.inflate(R.layout.child_item_female, null);
}
TextView tv = (TextView) convertView.findViewById(R.id.country_name);
ImageView iv = (ImageView) convertView.findViewById(R.id.flag);
tv.setText(child.getName().toString());
iv.setImageResource(child.getImage());
return convertView;
}