Question

我收到了这段代码：

    public static string DoPrefixCipherEncrypt(string strIn, byte[] btKey)
    {
        if (strIn.Length < 1)
            return strIn;

        // Convert the input string to a byte array 
        byte[] btToEncrypt = System.Text.Encoding.Unicode.GetBytes(strIn);
        RijndaelManaged cryptoRijndael = new RijndaelManaged();
        cryptoRijndael.Mode =
        CipherMode.ECB;//Doesn't require Initialization Vector 
        cryptoRijndael.Padding =
        PaddingMode.PKCS7;


        // Create a key (No IV needed because we are using ECB mode) 
        ASCIIEncoding textConverter = new ASCIIEncoding();

        // Get an encryptor 
        ICryptoTransform ictEncryptor = cryptoRijndael.CreateEncryptor(btKey, null);


        // Encrypt the data... 
        MemoryStream msEncrypt = new MemoryStream();
        CryptoStream csEncrypt = new CryptoStream(msEncrypt, ictEncryptor, CryptoStreamMode.Write);


        // Write all data to the crypto stream to encrypt it 
        csEncrypt.Write(btToEncrypt, 0, btToEncrypt.Length);
        csEncrypt.Close();


        //flush, close, dispose 
        // Get the encrypted array of bytes 
        byte[] btEncrypted = msEncrypt.ToArray();


        // Convert the resulting encrypted byte array to string for return 
        return (Convert.ToBase64String(btEncrypted));
    }

    private static List<int> GetRandomSubstitutionArray(string number)
    {
        // Pad number as needed to achieve longer key length and seed more randomly.
        // NOTE I didn't want to make the code here available and it would take too longer to clean, so I'll tell you what I did. I basically took every number seed that was passed in and prefixed it and  postfixed it with some values to make it 16 characters long and to get a more unique result. For example:
        // if (number.Length = 15)
        //    number = "Y" + number;
        // if (number.Length = 14)
        //    number = "7" + number + "z";
        // etc - hey I already said this is a hack ;)

        // We pass in the current number as the password to an AES encryption of each of the
        // digits 0 - 9. This returns us a set of values that we can then sort and get a 
        // random order for the digits based on the current state of the number.
        Dictionary<string, int> prefixCipherResults = new Dictionary<string, int>();
        for (int ndx = 0; ndx < 10; ndx++)
            prefixCipherResults.Add(DoPrefixCipherEncrypt(ndx.ToString(), Encoding.UTF8.GetBytes(number)), ndx);

        // Order the results and loop through to build your int array.
        List<int> group = new List<int>();
        foreach (string key in prefixCipherResults.Keys.OrderBy(k => k))
            group.Add(prefixCipherResults[key]);

        return group;
    }

来自此链接Encrypt a number to another number of the same length

我需要将“DoPrefixCypherEncrypt”转换/调整为AesManaged而不是RijdaelManaged。

谢谢你们

更新谢谢你的所有答案：

我最终找到了使用WP 8.1中可用类的另一种方法。

而不是：

        public static string DoPrefixCipherEncrypt(string strIn, byte[] btKey)
    {
        if (strIn.Length < 1)
            return strIn;

        // Convert the input string to a byte array 
        byte[] btToEncrypt = System.Text.Encoding.Unicode.GetBytes(strIn);

        AesManaged cryptoRijndael = new AesManaged();
        cryptoRijndael.Mode = CipherMode.ECB; cryptoRijndael.Padding = PaddingMode.PKCS7; //Mode Doesn't require Initialization Vector 

        // Create a key (No IV needed because we are using ECB mode) 
        ASCIIEncoding textConverter = new ASCIIEncoding();
        // Get an encryptor 
        ICryptoTransform ictEncryptor = cryptoRijndael.CreateEncryptor(btKey, null);
        // Encrypt the data... 
        MemoryStream msEncrypt = new MemoryStream();
        CryptoStream csEncrypt = new CryptoStream(msEncrypt, ictEncryptor, CryptoStreamMode.Write);

        // Write all data to the crypto stream to encrypt it 
        csEncrypt.Write(btToEncrypt, 0, btToEncrypt.Length); csEncrypt.Close(); //flush, close, dispose 
        // Get the encrypted array of bytes 
        byte[] btEncrypted = msEncrypt.ToArray();

        // Convert the resulting encrypted byte array to string for return 
        return (Convert.ToBase64String(btEncrypted));
    }

与非WinRT .NET兼容。

我能够使用：

    public static string DoPrefixCipherEncrypt(string strIn, byte[] btKey)
    {
        if (strIn.Length < 1)
            return strIn;

        IBuffer plainBuffer = CryptographicBuffer.ConvertStringToBinary(strIn, BinaryStringEncoding.Utf16LE);
        IBuffer keyMaterial = CryptographicBuffer.CreateFromByteArray(btKey);

        SymmetricKeyAlgorithmProvider symProvider = SymmetricKeyAlgorithmProvider.OpenAlgorithm(SymmetricAlgorithmNames.AesEcbPkcs7);
        // create symmetric key from derived password key
        CryptographicKey symmKey = symProvider.CreateSymmetricKey(keyMaterial);

        var buffEncrypted = CryptographicEngine.Encrypt(symmKey, plainBuffer, null);
        var strEncrypted = CryptographicBuffer.EncodeToBase64String(buffEncrypted);

        return strEncrypted;
    }

Answer 1

只需用AesManaged替换RijndaelManaged的实例化和声明：

AesManaged cryptoRijndael = new AesManaged();

我试过了，它运作得很好。我建议同样重命名一下cryptoRijndael变量名 - 但这不会改变代码功能的任何内容。

MSDN上有一个示例如何使用AesManaged语句：

AES算法本质上是Rijndael对称算法固定块大小和迭代计数。这个类的功能相同作为RijndaelManaged类的方式，但限制块为128位和不允许反馈模式。

所以只需用AesManaged替换RijndaelManaged的引用即可。只要您不在规定的限制范围内使用它就可以了。

严格来说，AES is a subset of Rijndael所以Rijndael Managed应该已经涵盖了你需要的任何内容。

来自Wikipedia：

AES基于两个比利时人开发的Rijndael密码[5] 密码学家，Joan Daemen和Vincent Rijmen，他们提交了一份文件在AES选择过程中向NIST提出建议。

将RijndaelManaged代码转换为AesManaged代码

1 个答案: