我正在编写一个mht脚本来解析mht文件并从父级中提取部分消息并将它们写入单独的mht文件
我写了下面的函数,它在file_location打开一个mht文件并搜索特定的content_id并将其写入一个新的mht文件
def extract_content(self, file_location, content_id,extension):
first_part = file_location.split(extension)[0]
#checking if file exists
new_file = first_part + "-" + content_id.split('.')[0] + extension
while os.path.exists(new_file):
os.remove(new_file)
with open(file_location, 'rb') as mime_file, open(new_file, 'w') as output:
***#Extracting the message from the mht file***
message = message_from_file(mime_file)
t = mimetypes.guess_type(file_location)[0]
#Walking through the message
for i, part in enumerate(message.walk()):
#Check the content_id if the one we are looking for
if part['Content-ID'] == '<' + content_id + '>':
***witing the contents***
output.write(part.as_string(unixfrom=False))
显然,在 application / pdf和application / octet-stream 的情况下,我无法在IE中打开输出部分。
我如何编写这些Content-Type,如application / pdf和 application / octet-stream in mht文件,以便我能够在IE中查看图像或pdf?
由于
答案 0 :(得分:1)
试试这个:
...
if m['Content-type'].startswith('text/'):
m["Content-Transfer-Encoding"] = "quoted-printable"
else:
m["Content-Transfer-Encoding"] = "base64"
m.set_payload(part.get_payload())
****Writing to output****
info = part.as_string(unixfrom=False)
info = info.replace('application/octet-stream', 'text/plain')
output.write(info)
...
告诉我它是否有效。