我正在尝试在电子邮件中发送多个文件,我收到了将其附加到电子邮件中的代码。
Intent sendIntent = new Intent(Intent.ACTION_SEND_MULTIPLE);
sendIntent.setType("application/octet-stream");
ArrayList<Uri> uris = new ArrayList<Uri>();
uris.add(0, Uri.parse("file://"+Environment.getExternalStorageDirectory()+ "/.file"));
File f = getActivity().getDatabasePath(".db");
Log.i(TAG,"DB path"+ f.getAbsolutePath());
uris.add(1, Uri.fromFile(f));
sendIntent.putParcelableArrayListExtra(Intent.EXTRA_STREAM, uris);
但是现在,我需要将它们压缩成单个zip文件然后我必须通过电子邮件发送它们。好吧,我看到了许多答案和想法,但我仍然无法得到一些明确的想法。你能帮助我解决这个问题。
答案 0 :(得分:23)
这些持久性是将数据存储到设备存储所必需的 Mainfest.xml文件
<uses-permission android:name="android.permission.WRITE_INTERNAL_STORAGE" />
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>
写入外部存储所需的许可(2018/10/04更新)
public static void verifyStoragePermissions(Activity activity) {
// Check if we have write permission
int permission = ActivityCompat.checkSelfPermission(activity, Manifest.permission.WRITE_EXTERNAL_STORAGE);
if (permission != PackageManager.PERMISSION_GRANTED) {
// We don't have permission so prompt the user
ActivityCompat.requestPermissions(
activity,
PERMISSIONS_STORAGE,
REQUEST_EXTERNAL_STORAGE
);
}
}
Zip功能
public void zip(String[] _files, String zipFileName) {
try {
BufferedInputStream origin = null;
FileOutputStream dest = new FileOutputStream(zipFileName);
ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(
dest));
byte data[] = new byte[BUFFER];
for (int i = 0; i < _files.length; i++) {
Log.v("Compress", "Adding: " + _files[i]);
FileInputStream fi = new FileInputStream(_files[i]);
origin = new BufferedInputStream(fi, BUFFER);
ZipEntry entry = new ZipEntry(_files[i].substring(_files[i].lastIndexOf("/") + 1));
out.putNextEntry(entry);
int count;
while ((count = origin.read(data, 0, BUFFER)) != -1) {
out.write(data, 0, count);
}
origin.close();
}
out.close();
} catch (Exception e) {
e.printStackTrace();
}
}
使用Zip功能
String[] s = new String[2];
// Type the path of the files in here
s[0] = inputPath + "/image.jpg";
s[1] = inputPath + "/textfile.txt"; // /sdcard/ZipDemo/textfile.txt
// first parameter is d files second parameter is zip file name
ZipManager zipManager = new ZipManager();
// calling the zip function
zipManager.zip(s, inputPath + inputFile);
解压缩功能
public void unzip(String _zipFile, String _targetLocation) {
//create target location folder if not exist
dirChecker(_targetLocatioan);
try {
FileInputStream fin = new FileInputStream(_zipFile);
ZipInputStream zin = new ZipInputStream(fin);
ZipEntry ze = null;
while ((ze = zin.getNextEntry()) != null) {
//create dir if required while unzipping
if (ze.isDirectory()) {
dirChecker(ze.getName());
} else {
FileOutputStream fout = new FileOutputStream(_targetLocation + ze.getName());
for (int c = zin.read(); c != -1; c = zin.read()) {
fout.write(c);
}
zin.closeEntry();
fout.close();
}
}
zin.close();
} catch (Exception e) {
System.out.println(e);
}
}
使用解压缩功能
ZipManager zipManager = new ZipManager();
zipManager.unzip(inputPath + inputFile, outputPath);
[来源:http://stacktips.com/tutorials/android/how-to-programmatically-zip-and-unzip-file-in-android]