Question

这是我的代码（对于testString的冗长道歉，我不太确定如何格式化它）：

testString = """{"id":"174833828503074873","classid":"217769142","instanceid":"0","amount":"1","pos":1},"174833828503117736":{"id":"174833828503117736","classid":"217769142","instanceid":"574274862","amount":"1","pos":2}asdf234sadf"""
sections = re.findall(r'{.*}', testString)
for section in sections:
    print section

我想提取以下两个字符串： {"id":"174833828503074873","classid":"217769142","instanceid":"0","amount":"1","pos":1} {"id":"174833828503117736","classid":"217769142","instanceid":"574274862","amount":"1","pos":2}

但是，当我打印这些部分时，它会提取第一个和第二个项目并将它们组合成一个字符串：

{"id":"174833828503074873","classid":"217769142","instanceid":"0","amount":"1","pos":1},"174833828503117736":{"id":"174833828503117736","classid":"217769142","instanceid":"574274862","amount":"1","pos":2}

任何人都知道我做错了什么？

Answer 1

你需要在?之后添加*量词来做一个不情愿的匹配（最短的匹配）。基本上*只会进行贪婪的匹配。

sections = re.findall(r'{.*?}', testString)

DEMO

>>> import re
>>> testString = """{"id":"174833828503074873","classid":"217769142","instanceid":"0","amount":"1","pos":1},"174833828503117736":{"id":"174833828503117736","classid":"217769142","instanceid":"574274862","amount":"1","pos":2}asdf234sadf"""
>>> sections = re.findall(r'{.*?}', testString)
>>> for section in sections:
...     print section
... 
{"id":"174833828503074873","classid":"217769142","instanceid":"0","amount":"1","pos":1}
{"id":"174833828503117736","classid":"217769142","instanceid":"574274862","amount":"1","pos":2}

Python正则表达式打印出字符串的各个部分

1 个答案: