Question

为什么fetch (PDO::FETCH_ASSOC)无法正常工作？如何在没有foreach循环的情况下从表中获取我想要的数据？我之前使用$statement变量来准备/执行另一个查询。这可能是问题吗？

try
{
    $database = new PDO ('mysql:host=localhost;dbname=youdonotneedtoknow;charset=utf8', 'youdonotneedtoknow', 'youdonotneedtoknow');
    $database -> setAttribute (PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $database -> setAttribute (PDO::ATTR_EMULATE_PREPARES, true);

    //Read
    $statement = $database -> prepare ('SELECT * FROM edit');
    $statement -> execute ();
    while ($row = $statement -> fetch (PDO::FETCH_ASSOC))
    {
        $windowTitle = $row ['windowTitle'];
        $bodyBackgroundColour = $row ['bodyBackgroundColour'];
        $divisionBackgroundColour = $row ['divisionBackgroundColour'];
    }
}
catch (PDOException $exception)
{
    die ('Error: ' . $exception -> getMessage () . '<br><br>' . 'Por favor diríjase a "index.php" en este mismo directorio y contacte a su administrador.');
}

Answer 1

这样做：

while ($row = $statement -> fetch (PDO::FETCH_ASSOC))
{
    switch ($row['id']) {
        case 'windowTitle':
            $windowTitle = $row ['value'];
            break;
        case 'bodyBackgroundColour':
            $bodyBackgroundColour = $row['value'];
            break;
        case 'divisionBackgroundColour':
            $divisionBackgroundColour = $row['value'];
            break;
    }
}

您也可以使用变量：

while ($row = $statement -> fetch (PDO::FETCH_ASSOC))
{
    ${$row['id']} = $row['value'];
}

我无法使用'fetch（PDO :: FETCH_ASSOC）'从表中获取数据

1 个答案: