Question

我有一个奇怪的情况，不太确定如何接近它。

我有2个单独的表格：

表A是提交

id
submitterQID
nomineeQID
story

表B是员工

QID
Name
Department

我试图获得按部门分组的提交总数以及提名总数。

这就是我的存储过程：

BEGIN
                SELECT   TOP 50 count(A.[nomineeQID]) AS totalNominations,
                                count(A.[subQID]) AS totalSubmissions,
                                B.[DepartmentDesc] AS department
                FROM     empowermentSubmissions AS A
                JOIN empTable AS B
                ON B.[qid] = A.[nomineeQID]
                WHERE A.[statusID] = 3
                AND A.[locationID] = @locale
                GROUP BY B.[Department]
                ORDER BY totalNominations DESC
                FOR      XML PATH ('data'), TYPE, ELEMENTS, ROOT ('root');
            END

这个问题是，JOIN仅由nomineeQID加入，而不是subQID加入。

我正在寻找的最终结果是：

部门客户服务部门提交了25份提名和90份提名

按两个计数的总和排序......

我试图在JOIN再次subQID，但被告知我不能两次加入同一张桌子。

有没有更简单的方法来实现这一目标？

Answer 1

这是一种情况，您需要相互独立地收集您的计数。当两个连接条件都满足时，使用两个左连接将导致第一个左连接中的某些行计数两次。您可以使用相关子查询或外部应用来收集您的方案，以收集不同条件的计数。我这里没有提供COUNT(CASE ... )选项，因为您在数据中没有任何一个或多个场景，您有两个外键到employees表。因此，设置样本数据：

declare @empowermentSubmissions table (submissionID int primary key identity(1,1), submissionDate datetime, nomineeQID INT, submitterQID INT, statusID INT, locationID INT)
declare @empTable table (QID int primary key identity(1,1), AreaDesc varchar(10), DepartmentDesc varchar(20))
declare @locale INT = 0
declare @n int = 1

while @n < 50
begin
    insert into @empTable (AreaDesc, DepartmentDesc) values ('Area ' + cast((@n % 2)+1 as varchar(1)), 'Department ' + cast((@n % 4)+1 as varchar(1)))
    set @n = @n + 1
end
set @n = 1
while @n < 500
begin
    insert into @empowermentSubmissions (submissionDate, nomineeQID, submitterQID, StatusID, locationID) values (dateadd(dd,-(cast(rand()*600 as int)),getdate()), (select top 1 QID from @empTable order by newid()), (select top 1 QID from @empTable order by newid()), 3 + (@n % 2) - (@n % 3), (@n % 2) )
    set @n = @n + 1
end

现在是OUTER APPLY选项：

SELECT TOP 50 E.DepartmentDesc, SUM(N.Nominations) Nominations, SUM(S.TotalSubmissions) TotalSubmissions
FROM @empTable E
    OUTER APPLY (
        SELECT COUNT(submissionID) Nominations
        FROM @empowermentSubmissions A
        WHERE A.statusID = 3
            AND A.nomineeQID = E.QID
            AND A.locationID = @locale
    ) N
    OUTER APPLY (
        SELECT COUNT(submissionID) TotalSubmissions
        FROM @empowermentSubmissions A
        WHERE A.statusID = 3
            AND A.submitterQID = E.QID
            AND A.locationID = @locale
    ) S
GROUP BY E.DepartmentDesc
ORDER BY SUM(Nominations) + SUM(TotalSubmissions) DESC

TSQL使用具有不同JOIN的相同表的多次计数

1 个答案: