Question

我有一个包含一些栅格文件的文件夹，如下所示：us_ppt_1971_2000_01.asc，us_tmax_1971_2000_02.asc，us_tmin_1971_2000_03.asc，...

我想从输入文件夹中打开这些文件，根据每个文件进行一些计算，并将结果保存在输出文件夹中。

所有代码都运行正常，如果我为每个输入文件创建一个包含我想要的新名称的字典，我甚至可以保存结果。但我永远不知道哪个输入文件以哪个名称保存。

所以现在我想打开每个文件，进行计算，然后使用从输入文件名中删除的较短名称保存新文件，比如“ppt_01”，这样我就能识别出来。

以下代码正在运行，但随机保存文件，这意味着，ppt保存为tmax或tmin与ppt相同：

import ...
workDirectory="I:\\PRISM\\M stuff"
inputDirectory=workDirectory+"\\in"
inputDirectoryPrism=workDirectory+"\\in\\prism"
resultsDirectory=workDirectory+"\\results" 
...
...

maps = ["PP1", "PP2", "PP3", "PP4", "PP5", "PP6", "PP7", "PP8", "PP9",  "PP10", "PP11", "PP12",
        "TMX1", "TMX2", "TMX3", "TMX4", "TMX5", "TMX6", "TMX7", "TMX8", "TMX9",  "TMX10", "TMX11", "TMX12",
        "TMN1", "TMN2", "TMN3", "TMN4", "TMN5", "TMN6", "TMN7", "TMN8", "TMN9",  "TMN10", "TMN11", "TMN12"]

nr=0

for file in glob.glob( os.path.join(inputDirectoryPrism, '*.asc') ):                                                
        ...
        some calculations
        ...
        # Process: Zonal Statistics as Table    
        # THIS IS WHERE I SAVE MY FILE
        arcpy.gp.ZonalStatisticsAsTable_sa(outputDirectory+"\\subcat_diss_shp.shp", "GRIDCODE", outputDirectory+"\\us_ppt_di", resultsDirectory+"\\"+maps[nr]+".dbf", "DATA", "MEAN")   
        nr = nr + 1

这是我正在尝试的代码，但它给出了错误“工作区是无效的输出工作区”：

import ...
workDirectory="I:\\PRISM\\M stuff"
inputDirectory=workDirectory+"\\in"
inputDirectoryPrism=workDirectory+"\\in\\prism"
resultsDirectory=workDirectory+"\\results" 
...
...

nr=0

for file in glob.glob( os.path.join(inputDirectoryPrism, '*.asc') ):                                                
        name1 = file[3:]
        name2= name1[:-16]
        name3= file[17:]
        name4=name3[:-3]
        ...
        some calculations
        ...
        # Process: Zonal Statistics as Table    
        # THIS IS WHERE I SAVE MY FILE          
        arcpy.gp.ZonalStatisticsAsTable_sa(outputDirectory+"\\subcat_diss_shp.shp", "GRIDCODE", outputDirectory+"\\us_ppt_di", resultsDirectory+"\\"+name2+name4[nr]".dbf", "DATA", "MEAN") 
        nr = nr + 1

看起来像resultsDirectory +“\”+ name2 + name4 [nr]“。dbf”不是存储文件的好方法。

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谢谢！

打开多个文件，剥离名称并在计算后保存

0 个答案: