SQL按日期选择最新的行

时间:2014-08-28 11:13:27

标签: sql select group-by max getlatest

我有大量数据每10分钟更新一次。

需要返回128个唯一ID,但只有最新值

当前代码

SELECT DISTINCT 
id, 
MAX(extractdate) AS [extractdate],
total,
used,
free

FROM
maintable
INNER JOIN datatable ON maintable.unkey = datatable.dataunkey

GROUP BY id, total, used, free

ORDER BY id

当前输出

id      extractdate                 total   used    free
1       2014-08-28 00:20:00.000     50      20      30
1       2014-08-28 00:30:00.000     50      30      20
1       2014-08-28 00:40:00.000     50      10      40
2       2014-08-28 00:20:00.000     50      20      30
2       2014-08-28 00:30:00.000     50      30      20
2       2014-08-28 00:40:00.000     50      25      25
etc etc

**DESIRED OUTPUT**

id      extractdate                 total   used    free
1       2014-08-28 00:40:00.000     50      10      40
2       2014-08-28 00:40:00.000     50      25      25
etc etc

2 个答案:

答案 0 :(得分:1)

应该工作,我只是在类似的秋天测试它,只是没有加入:

SELECT id, extractdate,total,used,free
FROM maintable m INNER JOIN datatable ON m.unkey = datatable.dataunkey
where extractdate = (select max(extractdate) from manitable m1 where m1.id = m.id) 
ORDER BY id

答案 1 :(得分:1)

尝试:

SELECT 
a.id,
a.extractdate,
a.total,
a.used,
a.free
FROM(
SELECT  
id, 
MAX(extractdate) AS [extractdate],
total,
used,
free,
ROW_NUMBER()OVER(partition by id ORDER BY MAX(extractdate) desc) AS rnk
FROM maintable
INNER JOIN datatable ON maintable.unkey = datatable.dataunkey
GROUP BY id, total, used, free )a
WHERE a.rnk = 1