Question

我有以下生成的JSON结果，想知道如何将结果分成2个变量：

JSON

{
    "data": [
        [
            {
                "source": "server1",
                "host": "pc1",
                "description": "SSH server is down on {HOSTNAME}",
            }
        ],
        [
            {
                "source": "server2",
                "host": "pc2",
                "description": "webapp down",
            }
        ]
    ],
    "error": {
        "server3": "Host is not allowed to connect to this MySQL server",
        "server4": "Can't connect to MySQL server",
    }
}

预期结果：

{
    "data": [
            {
                "source": "server1",
                "host": "pc1",
                "description": "SSH server is down on {HOSTNAME}",
            },
            {
                "source": "server2",
                "host": "pc2",
                "description": "webapp down",
            }
        ]
}

和

{
    "error": {
        "server3": "Host is not allowed to connect to this MySQL server",
        "server4": "Can't connect to MySQL server",
    }
}

PHP代码：

<?php
  include '../include/db_conn.php';
  print to_json(get_all_alert());
 $return = get_all_alert();
print to_json($return["data"]);
print to_json($return["error"]);
?>

php代码仍会将结果打印两次。感谢

Answer 1

你的json数据不正确你可以在这里查看：http://json.parser.online.fr/ 从每个数组部分删除额外的逗号。

试试这个：

<?php
$data1='{
    "data": [
        [
            {
                "source": "server1",
                "host": "pc1",
                "description": "SSH server is down on {HOSTNAME}"
            }
        ],
        [
            {
                "source": "server2",
                "host": "pc2",
                "description": "webapp down"
            }
        ]
    ],
    "error": {
        "server3": "Host is not allowed to connect to this MySQL server",
        "server4": "Cant connect to MySQL server"
    }
}';

$val_array = json_decode($data1,true);

print_r($val_array['data']);
print_r($val_array['error']);

Answer 2

嗯，你可能还有一条你可能不需要的额外线。

print to_json(get_all_alert());

删除它，你的问题可能会消失。

将JSON结果分离为变量

2 个答案: