Question

我想编写一个脚本，将所有'.py'文件添加到zip文件中。

这就是我所拥有的：

import zipfile
import os

working_folder = 'C:\\Python27\\'

files = os.listdir(working_folder)

files_py = []

for f in files:
    if f[-2:] == 'py':
        fff = working_folder + f
        files_py.append(fff)

ZipFile = zipfile.ZipFile("zip testing.zip", "w" )

for a in files_py:
    ZipFile.write(a, zipfile.ZIP_DEFLATED)

但是它会出错：

Traceback (most recent call last):
  File "C:\Python27\working.py", line 19, in <module>
    ZipFile.write(str(a), zipfile.ZIP_DEFLATED)
  File "C:\Python27\lib\zipfile.py", line 1121, in write
    arcname = os.path.normpath(os.path.splitdrive(arcname)[1])
  File "C:\Python27\lib\ntpath.py", line 125, in splitdrive
    if p[1:2] == ':':
TypeError: 'int' object has no attribute '__getitem__'

所以给出的文件名似乎不正确。

Answer 1

您需要将压缩类型作为关键字参数传递：

ZipFile.write(a, compress_type=zipfile.ZIP_DEFLATED)

如果没有关键字参数，您将给ZipFile.write()一个整数arcname参数，这会导致您看到arcname正常化时出现的错误。

Answer 2

根据上述指导，决赛是：（只是将它们放在一起以防它可能有用）

import zipfile
import os

working_folder = 'C:\\Python27\\'

files = os.listdir(working_folder)

files_py = []

for f in files:
    if f.endswith('py'):
        fff = os.path.join(working_folder, f)
        files_py.append(fff)

ZipFile = zipfile.ZipFile("zip testing3.zip", "w" )

for a in files_py:
    ZipFile.write(os.path.basename(a), compress_type=zipfile.ZIP_DEFLATED)

使用Python将文件列表添加到zip文件中

2 个答案: