Question

我有一张地图（由Json组成）如下，

{office=null, basicFunc=Brokerage Documents, id=null, status=Good, rcvdDateTime=08/01/2013 01:48:25, orgUnit=5L9890327, numOfPg=null, ip=null, content=null, btchName=ONLINE UPLOAD, docTypeCde=20130801, rqstId=null, filNm={subrecord={subfiled1=[value1, value2]}}, docSizeBytes=null, docId=1234567, doctype=ConversionAgreement}

并且POJO如下

public class IDocument {
    private String basicFunc;
    private String doctype;
    private String orgUnit;     
    @JsonDeserialize(as=Subrecord.class,contentAs=Subrecord.class)
    private Subrecord filNm;
    private String content;

}

public class Subrecord {    
    private List<Subfiled1> subField1;
    public List<Subfiled1> getSubField1() {
        return subField1;
    }
    public void setSubField(List<Subfiled1> subField1) {
        this.subField1 = subField1;
    }
}

public class Subfiled1 {
    private String value1;
    private String value2;

    public String getValue1() {
        return value1;
    }
    public void setValue1(String value1) {
        this.value1 = value1;
    }
    public String getValue2() {
        return value2;
    }
    public void setValue2(String value2) {
        this.value2 = value2;
    }
}

我正在使用jackson将地图转换为IDocument对象，如下所示

ObjectMapper mapper = new ObjectMapper();
IDocument iDocObj = mapper.convertValue(map, IDocument.class);

在iDocObj中我能够获得除filnm之外的所有内容的值，它将变为空

iDocObj.getFilNm（）。getSubField1（）= null;

如何为getFilNm定义值。

Answer 1

在你的JSON中它被命名为subfiled1而在java中它是subfield ...所以检查正确的命名约定

Java Map到java对象

1 个答案: