Question

我需要调用我在Web服务中传递的参数来获取sql server中的存储过程值，但是我知道这很快就打电话了

    <script type="text/javascript">
    function ExecuteAJAXCall() {
        $.ajax({
            type: "POST",
            url: "Name.asmx/GetUserDetails",
            data: "{'name':'" + $("#txtename").val() + "'}",
            contentType: "application/json; charset=utf-8",
            dataType: 'json',
            success: Callback_AJAXCall
        });
    };

    function Callback_AJAXCall(data) {
        document.getElementById("DataContainer").innerHTML = "the result is: " +     data.d;
    };
 </script>
  </head>
      <body>
 <form id="form1" runat="server">
 <div>
    <h2>
        AJAX call test page</h2>
         <input type="text" id="txtname" />
    <button type="button" onclick="ExecuteAJAXCall()";>
        Getdetails</button>
    <br />
    <br />
    <div id="DataContainer">
    </div>
    </div>

</form>
</body>
</html>

请检查我的代码以传递参数，如果我调用它显示reult为null

Answer 1

请尝试这个

function ExecuteAJAXCall() {
            $.ajax({
                type: "POST",
                url: "Name.asmx/GetUserDetails",
                data: {name:$("#txtename").val()},
                contentType: "application/json; charset=utf-8",
                dataType: 'json',
                success: Callback_AJAXCall
            });
        };

Answer 2

试试这个：因为您的数据类型是json，然后使用data[d]来调用您的结果数据。

function Callback_AJAXCall(data) {
   document.getElementById("DataContainer").innerHTML = "the result is: "+data[d];
};

Answer 3

   public string GetUserDetails(string name)
    {
    con.Open();
    SqlCommand cmd = new SqlCommand("exec sp_n @name='" + name + "'", con);
    cmd.CommandType = System.Data.CommandType.StoredProcedure;
    cmd.CommandText = "sp_n";
    cmd.Parameters.AddWithValue("@name", name);
    cmd.ExecuteNonQuery();
    SqlDataAdapter da = new SqlDataAdapter(cmd);
    DataSet ds = new DataSet();
    da.Fill(ds);
    con.Close();
    //XmlDataDocument xmldata = new XmlDataDocument(ds);
    //XmlElement xxx = xmldata.DocumentElement;
    return ds.GetXml();

    }

最初我没有返回ds.GetXml

如何在ajax jquery中调用参数

3 个答案: