Question

我正在尝试使用bash代码将一些python代码放在一起，并希望能够提供多个选项，这些选项接受您可以通过命令行输入的值。为此，我试图使用getopts，但我遇到了尝试设置默认值的问题。

我已经在网上查看了这个问题并且之前已经提出了类似的问题，我试图在主要的getopts代码之后使用冒号选项等答案并在之前放置一个默认值，这导致了下面的代码：

!/bin/bash

usage() { echo "Usage: $0 [-f <string] [-r <string>] [-t <string>] [-o <string>] [-s <5|10> [-e <1|2|3>] [-b <string>] [-q <string>]]" 1>&2; exit 1; }

q = "30"

b = "15"


while getopts ":f:r:t:o:s:e:b:q:" p; do
    case "${p}" in
        f)
            f=${OPTARG}

            ;;
        r)
            r=${OPTARG}
            ;;

        t)
            t=${OPTARG}
            ;;

        o)
            o=${OPTARG}
            ;;

        s)
            s=${OPTARG}
            ((s == 5 || s == 10)) || usage
            ;;

        e)
            e=${OPTARG}
            ((e == 1 || e == 2 || e == 3)) || usage
            ;;

        b)
            b=${OPTARG}
            ;;
        q)
            q=${OPTARG}
            ;;

        *)
            usage
            ;;
    esac
done

: ${q = 30}

: ${b = 15}

shift $((OPTIND-1))

if [ -z "${f}" ] || [ -z "${r}" ] || [ -z "${t}" ] || [ -z "${o}" ] || [ -z "${s}" ] || [ -z "${e}" ] || [-z "${b}"] || [-z "${q}"]; then
    usage
fi

b2 = ${b} + 2

echo "The following are your options."
echo "reverse read file = ${r}"
echo "forward read file = ${f}"
echo "type of file = ${t}"
echo "output identifier = ${o}"
echo "number of splits wanted (s) = ${s}"
echo "You have chosen to complete ${e} rounds of joining"
echo "Your have chosen that a consensus region of ${b} bases is needed for a match to be made."
if ["${e}" == 3]; then
  echo " For quality trimming you have select threshold cut off at ${q}"
fi

如上所述，我以前从未使用过getopts，如果有人能解释我如何纠正我的代码以设置b和q选项的默认值，我将不胜感激。

Answer 1

在shell分配中=周围没有空格！

错误

q = "30"

右

q="30"

错误的代码执行带有参数q和=的命令30。这不是预期的目的。

与：相似：

: ${q = 30}

应该是：

: ${q=30}

和相关但有些不同：

b2 = ${b} + 2

可以是：

b2=$((${b} + 2))
b2="${b} + 2"

（或许多次要变体），但请注意，这些结果会有很大差异。

在bash中使用getopts设置默认值

1 个答案:

错误

右