Question

json代码如下：

{"data":[
{"data":
{"created":"2014-02-26T21:14:56.662Z",
"district":"4fd43cc56d11340000000005",
"high_grade":"12",
"last_modified":"2014-02-26T21:14:56.665Z",
"location":{"address":"350 5th Avenue","city":"New York","state":"NY","zip":"10001"},
"low_grade":"9",
"name":"Clever High School",
"nces_id":"360008000000",
"phone":"(212) 555-1212",
"principal":{"name":"TheodoraKhan","email":"tdkhan@mailinator.com"},
"school_number":"02M800",
"sis_id":"02M800",
"state_id":"712345","id":"530e595026403103360ff9fd"},
"uri":"/v1.1/schools/530e595026403103360ff9fd"},

{"data":{"created":"2014-02-26T21:14:56.668Z","district":"4fd43cc56d11340000000005","high_grade":"5","last_modified":"2014-02-26T21:14:56.670Z","location":{"address":"110
菠萝街＆＃34;＆＃34;城市＆＃34;：＆＃34;布鲁克林＆＃34;＆＃34;状态＆＃34;：＆＃34; NY＆＃34;＆＃34;拉链＆＃34 ;: ＆＃34; 11201＆＃34;}＆＃34; low_grade＆＃34;：＆＃34;幼儿园＆＃34;＆＃34;名称＆＃34;：＆＃34;聪明小学＆＃34;，＆＃34; nces_id＆＃34;：＆＃34; 360007000000＆＃34;，＆＃34;电话＆＃34;：＆＃34;（718） 555-4567＆＃34;＆＃34;主＆＃34; {＆＃34;名称＆＃34;：＆＃34;塞西莉亚罗德里克＆＃34;＆＃34;电子邮件＆＃34;：＆＃34; ceciliar@mailinator.com"}＆＃34; school_number＆＃34;：＆＃34; 13K123＆＃34;＆＃34; sis_id＆＃34;：＆＃34; 13K123＆＃34;＆＃34; STATE_ID＆＃34;：＆＃34; 30890＆＃34;＆＃34; ID＆＃34;：＆＃34; 530e595026403103360ff9fe＆＃34;} ＆＃34; URI＆＃34;：＆＃34; /v1.1/schools/530e595026403103360ff9fe"}

Answer 1

我不太明白你在问什么。

但您可以使用以下内容：

$obj = json_decode($json_str);

Answer 2

尝试json_decode：

$data = {"data":"a"}:
$json = json_decode($data);
echo $json->data;

在PHP中解析json对象

2 个答案: