凯撒密码：如何从字典中打印*来自输入的所有*字母？

Question

当我使用输入＆＃34; abc＆＃34;运行它时，它只打印＆＃34; f＆＃34;而不是＆＃34; def＆＃34;我无法弄清楚为什么......帮助

code = raw_input("Enter your code: ")

translation = {"a": "d", "b": "e", "c": "f", "d": "g", "e": "h", "f": "i", "g": "j", "h": "k", "i": "l", "j": "m", "k": "n", "l": "o", "m": "p", "n": "q", "o": "r", "p": "s", "q": "t", "r": "u", "s": "v", "t": "w", "u": "x", "v": "y", "w": "z", "x": "a", "y": "b", "z": "c"}

lettered_code = list(code)

def translate(lettered_code):
    for letters in lettered_code:
        newanswer = translation[letters]
    return newanswer

print translate(lettered_code)

Answer 1

您只返回最后一次翻译，每次迭代都会newanswer = translation[letters]，因此您只能看到最后一次。

将每个新char添加到字符串中：

def translate(lettered_code):
    new_answer = "" # set variable outside the for loop to an empty string
    for letters in lettered_code:
        new_answer += translation[letters] # add each translated letter to new_answer
    return new_answer # return all joined letters

您不需要lettered_code = list(code)，您可以直接迭代字符串，只需将code传递到您的函数中。

您还可以使用join和list comprehension创建已翻译的字符列表，并将它们连接成一个字符串：

def translate(lettered_code):
    "".join([translation[letters] for letters in lettered_code ])

Answer 2

你要早点回来，你想要

def translate(lettered_code):
    return [translation[letter] for letter in lettered_code]