Question

我有两个表，如下所示，需要加入两个表，需要获取结果表。

有人可以帮我吗？

New_Table               
Emp CodeEmp Name    BF  OOF TB
11111   AAAA        Y   Off 1
22222   BBBB        Y   Off 0.75
22222   BBBB        Y   Off 0.25
33333   CCCC        Y   On  0.98
44444   DDDD        Y   Off 1
55555   EEEE        Y   Off 1

Old_Table               
Emp Code    Emp Name       BF   OOF TB
11111       AAAA           Y    Off 1
22222       BBBB           Y    Off 0.25
22222       BBBB           Y    Off 0.75
33333       CCCC           Y    Off 0.98



Result              
Emp Code    Emp Name    BF  OOF TB
44444       DDDD        Y   Off 1
55555       EEEE        Y   Off 1

我已经尝试了下面的SQL查询购买我得到的Emp Code 222222我不需要，因为Emp Code 222222的TB总和相等，即1 = 1.

INSERT INTO Result ([Emp Code]
      ,[Emp Name]
      ,[BF]
      ,[OOF]
      ,[TB])
SELECT a.[Emp Code]
      ,a.[Emp Name]
      ,a.[BF]
      ,a.[OOF]
      ,a.[TB]
 FROM New_Table a left join Old_Table b 
 on a.[Emp Code] = b.[Emp Code] where 
 a.[BF] = 'Y' and a.[OOF] = b.[OOF] and a.[TB] > b.[TB]
 and a.[TB] > 0.5 ;

Answer 1

使用SUM，GROUP BY和HAVING子句。

INSERT INTO Result ([Emp Code]
      ,[Emp Name]
      ,[BF]
      ,[OOF]
      ,[TB])
SELECT a.[Emp Code]
      ,a.[Emp Name]
      ,a.[BF]
      ,a.[OOF]
      ,sum(a.[TB])
 FROM New_Table a left join Old_Table b 
 on a.[Emp Code] = b.[Emp Code] where 
 a.[BF] = 'Y' and a.[OOF] = b.[OOF]
 and a.[TB] > 0.5 
 group by 
    a.[Emp Code]
      ,a.[Emp Name]
      ,a.[BF]
      ,a.[OOF]
 having sum(a.[TB]) > sum(b.[TB])

Answer 2

试试这个：

AND (a.TB + COALESCE(B.TB, 0)) != 1

这将为你消除22222。

或者，您可以尝试子查询。

and a.[Emp Code] not in (select [Emp Code] from New_Table group by [Emp Code] 
having sum(TB) = 1)

您可以将任何where子句限制添加到您需要的子查询中。

Answer 3

USE EXCEPT运营商查找新记录。我只修改了你的查询。你能试试下面的代码吗？

INSERT INTO Result ([Emp Code]
          ,[Emp Name]
          ,[BF]
          ,[OOF]
          ,[TB])
    SELECT a.[Emp Code]
          ,a.[Emp Name]
          ,a.[BF]
          ,a.[OOF]
          ,a.[TB]
     FROM New_Table a left join Old_Table b 
     on a.[Emp Code] = b.[Emp Code] where 
     a.[BF] = 'Y' and a.[OOF] = b.[OOF] and a.[TB] > b.[TB]
    group by a.[Emp Code]
          ,a.[Emp Name]
          ,a.[BF]
          ,a.[OOF]
          ,a.[TB]
    having sum(a.tb)>1

SQL Server带有内连接的where子句中两列的总和

3 个答案: