Question

我有两张这样的桌子......

表1

+------+----------+-----+--------+
| Year |  Runner  | Age | Result |
+------+----------+-----+--------+
| 2004 | Runner 1 |   3 | Won    |
| 2004 | Runner 2 |   4 | Lost   |
| 2004 | Runner 3 |   3 | Lost   |
| 2005 | Runner 1 |   3 | Lost   |
| 2005 | Runner 2 |   3 | Lost   |
| 2005 | Runner 3 |   4 | Won    |
| 2006 | Runner 1 |   4 | Won    |
| 2006 | Runner 2 |   3 | Lost   |
| 2006 | Runner 3 |   4 | Lost   |
+------+----------+-----+--------+

表2

+-------+----------+-----+
| RCNum |  Runner  | Age |
+-------+----------+-----+
|     1 | Runner 1 |   3 |
|     2 | Runner 2 |   4 |
|     3 | Runner 3 |   3 |
|     4 | Runner 4 |   3 |
|     5 | Runner 5 |   3 |
+-------+----------+-----+

现在我将使用......

    $numbers = mysql_query("SELECT age,
        sum(case when result <> ''then 1 else 0 end) Sec1Picks,
        sum(case when result = 'Won' then 1 else 0 end) Sec1Wins
    FROM table1
    GROUP BY age
    ORDER BY age ASC");

while($row = mysql_fetch_array($numbers, MYSQL_ASSOC)) {
echo "(".$row['Age']."yo) ".$row['Sec1Wins']."-".$row['Sec1Picks']; }

哪个会给我年龄，然后是选秀权和获胜者的数量，但我想要做的是在此之后我想要包括那些属于那个因素的RCNum。

所以例如3yo会输出..

（3yo）1-5（1 3 4 5）
（4yo）2-4（2）

我的技能是基本的，所以我不确定如何实现这一点，所以任何帮助将不胜感激！谢谢你的进步！

修改

我目前正在使用......如下所示

SELECT t1.age
     , SUM(CASE WHEN t1.result <> '' THEN 1 ELSE 0 END) Sec1Picks
     , SUM(CASE WHEN t1.result = 'Won' THEN 1 ELSE 0 END) Sec1Wins
     , GROUP_CONCAT(DISTINCT t2.rcnum ORDER BY rcnum SEPARATOR ' ') rcnums
  FROM table2 t2
  RIGHT
  JOIN table1 t1
    ON t1.age= t2.age
 GROUP 
    BY t1.age;

这给了我这个......

+-----------+-----------+----------+---------------------------+
|   age     | Sec1Picks | Sec1Wins |          rcnums           |
+-----------+-----------+----------+---------------------------+
|         3 |       420 |       14 | 8 9 13 21 22 25 27        |
|         4 |       352 |       24 | 6 7 11 16 17 19 20 29     |
|         5 |       470 |       10 | 1 2 3 5 10 15 18 23 24 26 |
|         6 |        64 |        6 | 12 14                     |
|         7 |        25 |        1 | 4                         |
|         8 |         7 |        0 | NULL                      |
|         9 |         2 |        0 | 28 30                     |
+-----------+-----------+----------+---------------------------+

但是正在发生的事情是，在rcnums列中插入的每个数字都会在Picks / Wins列中再次添加统计数据！

在Picks / Wins列中，我只想在Table1中计算，因此3yo将是60而2则不是420和14.我将如何更改编码以实现此目的？

Answer 1

SELECT t2.age
     , SUM(CASE WHEN t1.result <> '' THEN 1 ELSE 0 END) Sec1Picks
     , SUM(CASE WHEN t1.result = 'Won' THEN 1 ELSE 0 END) Sec1Wins
     , GROUP_CONCAT(DISTINCT t2.rcnum ORDER BY rcnum SEPARATOR ' ') rcnums
  FROM table2 t2
  LEFT
  JOIN table1 t1
    ON t1.runner = t2.runner
 GROUP 
    BY t2.age;

来自一个表中的两个表的信息

1 个答案: