Question

使用以下MSSQL Select语句在返回IPv4地址时工作正常但在DB中找到IPv6地址时脚本错误：

传递给LEFT或SUBSTRING函数的长度参数无效。

脚本：

select [column 3]
from [IPs]
where [dbo].[IP2INT]
    (
        RIGHT(
            LEFT(
                [IPBan_Log],
                CHARINDEX(',', [IP_Log]) - 1
            ),
            LEN(
                LEFT(
                    [IP_Log],
                    CHARINDEX(',', [IP_Log]) - 1
                )
            ) - CHARINDEX('ss', [IP_Log]) - 2
        )
    ) between [Column 0] and [Column 1]
)

如何更改脚本以处理IPv6（fe80 :: d474：f998：3980：360d）以及IPv4（91.204.2121.163）？

我们的自定义功能：

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER function [dbo].[IP2INT](@ipAddress varchar(20)) 
RETURNS bigint 
AS 
BEGIN 

DECLARE @FirstDot int, @SecondDot int, @ThirdDot int, 
        @FirstOctet varchar(3), @SecondOctet varchar(3), 
        @ThirdOctet varchar(3), @FourthOctet varchar(3), 
        @Result bigint 

    SET @FirstDot = CHARINDEX('.', @ipAddress) 
    SET @SecondDot = CHARINDEX('.', @ipAddress, @FirstDot + 1) 
    SET @ThirdDot = CHARINDEX('.', @ipAddress, @SecondDot + 1) 

    SET @FirstOctet = SUBSTRING(@ipAddress, 1, @FirstDot - 1) 
    SET @SecondOctet = SUBSTRING(@ipAddress, @FirstDot + 1, @SecondDot - @FirstDot - 1) 
    SET @ThirdOctet = SUBSTRING(@ipAddress, @SecondDot + 1, @ThirdDot - @SecondDot - 1) 
    SET @FourthOctet = SUBSTRING(@ipAddress, @ThirdDot + 1, 3) 

    SET @Result = 16777216 * CAST(@FirstOctet as bigint) + 
                  65536    * CAST(@SecondOctet as bigint) + 
                  256      * CAST(@ThirdOctet as bigint) + 
                             CAST(@FourthOctet as bigint) 
    RETURN(@Result); 


END

Answer 1

我看不到为tsql记录的本机ip2int函数，所以我假设你有自己的实现，它不兼容IPv6，只在它无法解析的任何地址（如IPv6）上返回NULL或类似内容。如果你愿意提供你的实现，可以看看。

SQL嵌套使用IPv4 / IPv6选择

1 个答案: