我使用Mysql数据库版本5.5.24-log。
在此表中,我无法对字段Premium_name的值进行计数和分组。
在输出中我需要2作为最终值,因为在表中只有两个Premium_name:HYDROSPEED和GLOCKENSPIELMEMORIAL。
提前谢谢。
SELECT
COUNT(*), Premium_name
FROM
`table_premium`
GROUP BY
Premium_name;
+----------+----------------------+
| COUNT(*) | Premium_name |
+----------+----------------------+
| 2 | GLOCKENSPIELMEMORIAL |
| 6 | HYDROSPEED |
+----------+----------------------+
2 rows in set
+--------------+------------------+----------------------+--------------+
| Premium_area | Premium_sub_area | Premium_name | Premium_code |
+--------------+------------------+----------------------+--------------+
| 51PD | 51PDK1 | HYDROSPEED | 48069794 |
| 51PD | 51PDK1 | HYDROSPEED | 48069795 |
| 51PD | 51PDK1 | HYDROSPEED | 49301672 |
| 51PD | 51PDK1 | HYDROSPEED | 52480075 |
| 51PD | 51PDK1 | HYDROSPEED | 52646404 |
| 51PD | 51PDK1 | HYDROSPEED | 91189540 |
| 51PD | 51PDK2 | GLOCKENSPIELMEMORIAL | 45824206 |
| 51PD | 51PDK2 | GLOCKENSPIELMEMORIAL | 48479834 |
+--------------+------------------+----------------------+--------------+
答案 0 :(得分:0)
试试这个:
SELECT COUNT(1) AS PREMIUMS FROM
(SELECT
DISTINCT Premium_name
FROM
`table_premium`)CS
答案 1 :(得分:0)
SELECT COUNT(DISTINCT Premium_name), Premium_name
FROM
`table_premium`
答案 2 :(得分:0)
SELECT COUNT(DISTINCT Premium_name),Premium_name FROM table_premium group by Premium_name