Question

我有2个下拉选择基于选择即时获取json数据来显示树但是我不能在选择中显示树但是如果我运行特定的jsp即可获得树中的任何选择。但是我无法追加子节点。每件事都来自数据库。基于数据必须显示树，并且每次都在渲染相同的树。

它看起来像 -

root node
|__NodeA
|__NodeB
|__NodeC

如果我选择NodeA相同的根节点 - nodeA - NodeB - NodeC 来了。

基本上我需要选择节点子应该追加下一个。请有人帮助我。

结果应该是

root node
|__NodeA
|__NodeB
|__NodeC

如果我选择nodeA

root node
|__NodeA
 |--child1
 |--child2
|__NodeB
|__NodeC

像那样。

这是我的jsp ..

<head>
    <sj:head jqueryui="true" jquerytheme="showcase" debug="false"/>
</head>    
<script>
    $.subscribe('treeClicked', function(event, data) {

        var item = event.originalEvent.data.rslt.obj;
        alert('Clicked ID : ' + item.attr("id"));
    });


    function gettree()
    {

        document.forms.tree.action="echo.action";
        document.forms.tree.submit();
    }
</script>

<body>
    <s:form name="tree">
        <s:label name="Sataion">Station</s:label>
        <s:select list="stationMap" name="stationId" id="stationid" headerValue=--   Select--" headerKey="-1" />

        <s:submit value="Submit" onclick="gettree();" />
        enter code here>


    <s:url action="echo" id="echo"/>

    <s:url action="childNodeexecute" id="childNodeexecute"></s:url>
    <sjt:tree  
        id="echo" 
        href="%{echo}"
        jstreetheme = "apple"
        rootNode="nodes" 
        onClickTopics="treeClicked"
        nodeHrefParamName="childNodeexecute"
        childCollectionProperty="children"
        nodeIdProperty="stationId" 
        nodeHref="%{childNodeexecute}"


        />

    </s:form>
</body>

我的动作类

public String execute（）{

    Map session = ActionContext.getContext().getSession();
    //session.get("stationMap");
    setStationMap((Map<Integer, String>) session.get("stationMap"));
     AppRejectDao dao = new AppRejectDao();
     setTest("hello");

    List<DistributonNodesnew> listvalues =dao.selectediddetails(getStationId());
    session.put("listvalues", listvalues);

    for (DistributonNodesnew distributonNodesnew : listvalues) {
          TreeNode nodeA = new TreeNode();
        nodeA.setId(distributonNodesnew.getDistributionNodeID());
        nodeA.setTitle(distributonNodesnew.getDistributionNodeName());
          nodes.add(nodeA);
    }
    return SUCCESS;      }



public String childNodeexecute()
    {
          Map session = ActionContext.getContext().getSession();
          List<DistributonNodesnew> listvalues;
            TreeNode nodeA = new TreeNode();
             AppRejectDao dao = new AppRejectDao();
          listvalues = (List<DistributonNodesnew>) session.get("listvalues");
           setStationMap((Map<Integer, String>) session.get("stationMap"));
          for (DistributonNodesnew distributonNodesnew : listvalues) {
              if(distributonNodesnew.getDistributionNodeID() == null ? nodeA.getId() == null : distributonNodesnew.getDistributionNodeID().equals(nodeA.getId()))
              {
                   List<DistributonNodesnew> listvaluesnew =dao.selectediddetails(Integer.parseInt(nodeA.getId()));
                   for (DistributonNodesnew distributonNodesnew1 : listvaluesnew) {
                        TreeNode childnode = new TreeNode();
                     nodeA.setChildren(new LinkedList<TreeNode>());
                     childnode.setId(distributonNodesnew1.getDistributionNodeID());
                     childnode.setTitle(distributonNodesnew1.getDistributionNodeName());
                    nodeA.getChildren().add(childnode);
                    nodes.add(nodeA);

                  }

              }

        }
        return SUCCESS;

    }

和我的struts.xml

/jsp/AppRejstruts2/tree.jsp

     <action name="echo" class="com.myapp.struts2.Apprej.TreeDynamicAction"  >
       <result name="success" type="json" >
        <param name="root">nodes</param>/jsp/AppRejstruts2/tree.jsp</result>  

    </action>

    <action name="childNodeexecute" class="com.myapp.struts2.Apprej.TreeDynamicAction" method="childNodeexecute">
       <result name="success" type="json" >
            <param name="root">nodes</param>/jsp/AppRejstruts2/tree.jsp</result>  

    </action>

struts2 + jquery树不起作用

0 个答案: