Question

有很多谷歌搜索结果可以解答这个问题。但是，似乎没有一个对我有用。因此，我正在创建这个问题并回答它以供将来参考以及可能通过Google访问此主题的任何其他人。

Answer 1

以下是查询：

select sum(mbytes)/1024, database from (
select trim(pgdb.datname) as Database,
trim(a.name) as Table, b.mbytes
from stv_tbl_perm a
join pg_database as pgdb on pgdb.oid = a.db_id
join (select tbl, count(*) as mbytes
from stv_blocklist group by tbl) b on a.id=b.tbl
where a.slice=0
order by db_id, name)
group by database;

<强>输出：

?column? |   database
----------+---------------
       62 | db1
       33 | db2
       33 | db3
        2 | db4
       37 | db5
       34 | db6
       35 | db7
       59 | db8
        2 | db9
       26 | db10
        2 | db11
       72 | db12
       36 | db13
       41 | db14

注意：以上数字以GB为单位

Answer 2

在查找表的磁盘空间使用情况时，请使用以下查询：

select
    trim(pgdb.datname) as Database,
    trim(pgn.nspname) as Schema,
    trim(a.name) as Table,
    b.mbytes,
    a.rows
from (
    select db_id, id, name, sum(rows) as rows
    from stv_tbl_perm a
    group by db_id, id, name
) as a
join pg_class as pgc on pgc.oid = a.id
join pg_namespace as pgn on pgn.oid = pgc.relnamespace
join pg_database as pgdb on pgdb.oid = a.db_id
join (
    select tbl, count(*) as mbytes
    from stv_blocklist
    group by tbl
) b on a.id = b.tbl
order by mbytes desc, a.db_id, a.name;

Amazon RedShift：如何查找数据库大小

2 个答案: