我的问题让我感到难过，而且我不知道在哪里教育自己应对这一挑战。
我有一群孩子的年龄，我从用php和mysql构建的家庭事件注册数据库中的数据算起来。孩子们正在报名，宣布部落群体和他们所属的年龄。在任何给定时间都有多个活动计划进行注册。在任何时候，活动主持人都需要查看年龄计数。每列中的孩子总数在mysql窗口中工作，但不在html中。到目前为止，mysql结果如下所示：
custom item_number1 Age 7 Age 8 ....
703198 Apache 1 NULL
703198 Arapahoe 2 5
703198 Aztec 1 NULL
703198 Blackfoot 1 5
703198 Cherokee 1 1
703198 Chippewa 1 1
703198 Creek 1 2
703198 Fox 1 1
703198 Iroquois 1 NULL
703198 Mohawk NULL 4
703198 Pawnee 1 2
703198 Yellowknives 2 1
703198 All Tribes 13 22
以下是代码：
<?php
$query = "SELECT 703198 AS custom, item_name1
, COALESCE(item_number1,'All Tribes') AS item_number1
, COUNT(CASE WHEN Ages = 4 THEN 4 ELSE NULL END) AS 'Age 4'
, COUNT(CASE WHEN Ages = 5 THEN 5 ELSE NULL END) AS 'Age 5'
, COUNT(CASE WHEN Ages = 6 THEN 6 ELSE NULL END) AS 'Age 6'
, COUNT(CASE WHEN Ages = 7 THEN 7 ELSE NULL END) AS 'Age 7'
, COUNT(CASE WHEN Ages = 8 THEN 8 ELSE NULL END) AS 'Age 8'
, COUNT(CASE WHEN Ages = 9 THEN 9 ELSE NULL END) AS 'Age 9'
, COUNT(CASE WHEN Ages = 10 THEN 10 ELSE NULL END) AS 'Age 10'
, COUNT(CASE WHEN Ages = 11 THEN 11 ELSE NULL END) AS 'Age 11'
, COUNT(CASE WHEN Ages = 12 THEN 12 ELSE NULL END) AS 'Age 12'
, COUNT(CASE WHEN Ages = 13 THEN 13 ELSE NULL END) AS 'Age 13'
, COUNT(CASE WHEN Ages = 14 THEN 14 ELSE NULL END) AS 'Age 14'
, COUNT(CASE WHEN Ages = 15 THEN 15 ELSE NULL END) AS 'Age 15'
, COUNT(CASE WHEN Ages = 16 THEN 16 ELSE NULL END) AS 'Age 16'
, COUNT(CASE WHEN Ages = 17 THEN 17 ELSE NULL END) AS 'Age 17'
FROM ( SELECT item_number1
, item_name1
, item_name3 AS Item
, item_number3 AS Ages
FROM tbl_pp_transactions
WHERE custom = 703198
AND item_name3 = 'Daughter'
AND item_number3 IN (4,5,6,7,8,9,10,11,12,13,14,15,16,17)
UNION ALL
SELECT item_number1
, item_name1
, item_name4 AS Item
, item_number4 AS Ages
FROM tbl_pp_transactions
WHERE custom = 703198
AND item_name4 = 'Daughter'
AND item_number4 IN (4,5,6,7,8,9,10,11,12,13,14,15,16,17)
UNION ALL
SELECT item_number1
, item_name1
, item_name5 AS Item
, item_number5 AS Ages
FROM tbl_pp_transactions
WHERE custom = 703198
AND item_name5 = 'Daughter'
AND item_number5 IN (4,5,6,7,8,9,10,11,12,13,14,15,16,17)
UNION ALL
SELECT item_number1
, item_name1
, item_name6 AS Item
, item_number6 AS Ages
FROM tbl_pp_transactions
WHERE custom = 703198
AND item_name6 = 'Daughter'
AND item_number6 IN (4,5,6,7,8,9,10,11,12,13,14,15,16,17)
) AS dt
GROUP
BY item_number1 WITH ROLLUP";
?>
我计划在do / while循环工作后将其缩短。我想使用准备好的＆gt;语句方法将其转换为html。但我不认为我的绑定名称是正确的。这就是我所拥有的：
<?php
if ($stmt = $con->prepare($query)) {
$stmt->execute();
$stmt->bind_result($custom, $item_name1, $item_number1, $Ages, $Item, $Item1, $Item3, $Item5, $Item7, $Item9, $Item11, $Item13, $Item15, $Item17, $Item19, $Item21, $Item23, $Item25);
?>
<table border="1" cellpadding="1">
<tr>
<th>Tribe</th>
<th>Age 4</th>
<th>Age 5</th>
<th>Age 6</th>
<th>Age 7</th>
<th>Age 8</th>
<th>Age 9</th>
<th>Age 10</th>
<th>Age 11</th>
<th>Age 12</th>
<th>Age 13</th>
<th>Age 14</th>
<th>Age 15</th>
<th>Age 16</th>
<th>Age 17</th>
</tr>
<?php
while ($stmt->fetch()) {
echo "<tr class='body_black'>";
printf("
<td><strong>%s</strong></td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
<td align='center'>%s</td>
", $item_number1, $Ages, $Item, $Item1, $Item3, $Item5, $Item7, $Item9, $Item11, $Item13, $Item15, $Item17, $Item19, $Item21, $Item23, $Item25);
echo "</tr>";
}
$stmt->close();
}
?>
</table>
任何建议或方向都会很棒？
由于
答案 0 :(得分：0)
这是最后的答案。标签需要从$ Item更改为$ Ages
$stmt->bind_result($custom, $item_name1, $item_number1, $Ages, $Ages1, $Ages3, $Ages5, $Ages7, $Ages9, $Ages10, $Ages13, $Ages15, $Ages17, $Ages19, $Ages21, $Ages23, $Ages25);
", $item_number1, $Ages, $Ages1, $Ages3, $Ages5, $Ages7, $Ages9, $Ages10, $Ages13, $Ages15, $Ages17, $Ages19, $Ages21, $Ages23, $Ages25);