Question

有谁知道为什么XSLT转换会在输出（html）中添加一些不在XSL模板中的内容？

查看下面的示例，我试图摆脱日期（请参阅输出）。

xsl模板

<?xml version="1.0" encoding="utf-8"?>  
<xsl:stylesheet version="1.0"
xmlns:php="http://php.net/xsl"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:s="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:a="http://schemas.datacontract.org/2004/Common.Akol"
xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> 
<!-- Edited by Adrian -->

<xsl:output method="html" encoding="UTF-8" indent="yes"/>

<xsl:template match="GetDriverDataResult">

<hr />

trans key:
<xsl:value-of select="a:driverInformationResponse/a:TransKey" />

trans key 2:
<xsl:value-of select="a:driverInformationResponse/a:TransKey" />

</xsl:template>
</xsl:stylesheet>

XML

<?xml version="1.0"?>
<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/" xmlns:u="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd">
  <s:Header>
    <o:Security xmlns:o="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" s:mustUnderstand="1">
      <u:Timestamp u:Id="_0">
        <u:Created>2014-08-27T00:29:39.204Z</u:Created>
        <u:Expires>2014-08-27T00:34:39.204Z</u:Expires>
      </u:Timestamp>
    </o:Security>
  </s:Header>
  <s:Body>
    <GetDriverDataResponse>
      <GetDriverDataResult xmlns:a="http://schemas.datacontract.org/2004/Common.Akol" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
        <a:driverInformationResponse>
          <a:TransKey>C00029540</a:TransKey>
          <a:Status>Success</a:Status>
        </a:driverInformationResponse>
      </GetDriverDataResult>
    </GetDriverDataResponse>
  </s:Body>
</s:Envelope>

OUPUT

2014-08-27T00:29:39.204Z
2014-08-27T00:34:39.204Z


trans key:
C00029540

trans key 2:
C00029540

Answer 1

默认情况下，built-in template rules将文本节点复制到输出XML文档。

要抑制此行为，请添加此模板以匹配文本节点，并且不对它们执行任何操作：

  <xsl:template match="text()"/>

为什么XSLT转换输出日期？ XML是SOAP响应

1 个答案: