我有一张oracle 10街道名表。它包含官方街道名称和各种替代名称。我正在尝试创建一个选项，列出官方街道名称和streetid最多3个名称的替代名称。
该表格如
ID STID STDIR STREET_NAME SUFFIX POSTDIR STREET_NAME_TYPE
146 585 E David DR STREET
357 821 S Front Nine DR STREET
51 483 S Colchester CT STREET
766 250 E Bluebird LN STREET
758 250 Blue Bird LN ALIAS
785 271 S Breeden RD STREET
647 109 Arbutus RD HISTORIC
439 911 E Hackers Creek RD STREET
196 642 E Dora RD STREET
572 22 E 1st Avenue Sanders STREET
1128 22 1st AVE ALIAS
1129 22 1st Ave Sanders ALIAS
2782 22 First Avenue Sanders ALIAS
578 28 W 20th ST STREET
2464 4379 S Tech Park BLVD HISTORIC
2988 4379 S Cooperative WAY STREET
...
我想得到像
这样的东西STIDREAL_STREET_NAME ALIAS1 ALIAS2 ALIAS3
585 E David DR
112 E Bluebird LN Blue Bird LN
271 S Breeden RD
22 E 1st Avenue Sanders 1st AVE 1st Ave Sanders First Avenue Sanders
...
但我为任何具有替代名称的街道获取重复值。
STIDREAL_STREET_NAME ALIAS1 ALIAS2 ALIAS3
585 E David DR
112 E Bluebird LN Blue Bird LN Blue Bird LN Blue Bird LN
911 E Hackers Creek RD
22 E 1st Avenue Sanders 1st Ave Sanders 1st Ave Sanders 1st AVE
22 E 1st Avenue Sanders 1st Ave Sanders First Avenue Sanders 1st Ave Sanders
22 E 1st Avenue Sanders 1st Ave Sanders 1st Ave Sanders 1st Ave Sanders
22 E 1st Avenue Sanders 1st Ave Sanders First Avenue Sanders First Avenue Sanders
22 E 1st Avenue Sanders 1st Ave Sanders 1st AVE 1st AVE
22 E 1st Avenue Sanders 1st Ave Sanders First Avenue Sanders 1st AVE
...
这是我使用的查询
SELECT
msn.street_id AS stid,
rtrim(msn.street_direction_code) || ' '
|| msn.street_name || ' '
|| msn.street_type_suffix_code || ' '
|| rtrim(msn.post_direction_suffix_code) as real_street_name,
asn1.alias1,
asn2.alias2,
asn3.alias3
FROM eng.mast_street_names msn,
(SELECT street_id, rtrim(street_direction_code) || ' ' || street_name || ' '
|| street_type_suffix_code || ' ' || rtrim(post_direction_suffix_code) AS alias1
FROM eng.mast_street_names
WHERE street_name_type != 'STREET') asn1,
(SELECT street_id, rtrim(street_direction_code) || ' ' || street_name || ' '
|| street_type_suffix_code || ' ' || rtrim(post_direction_suffix_code) AS alias2
FROM eng.mast_street_names
WHERE street_name_type != 'STREET') asn2,
(SELECT street_id, rtrim(street_direction_code) || ' ' || street_name || ' '
|| street_type_suffix_code || ' ' || rtrim(post_direction_suffix_code) AS alias3
FROM eng.mast_street_names
WHERE street_name_type != 'STREET') asn3
WHERE msn.street_name_type = 'STREET'
AND msn.street_id = asn1.street_id (+)
AND msn.street_id = asn2.street_id (+)
AND msn.street_id = asn3.street_id (+)
;
我尝试过各种方法来分组或计算行数较差且效果较差的行。谢谢你的帮助。