Question

我想正确编译以下代码：

#include <boost/units/systems/si.hpp>
#include <boost/units/base_units/metric/hour.hpp>

int main(int argc, char **argv) {
  using namespace boost::units;
  quantity<si::time> t = 2.0 * metric::hour_base_unit::unit_type(); 
}

使用gcc，我收到以下错误：

error: conversion from ‘boost::units::multiply_typeof_helper<double, boost::units::unit<boost::units::list<boost::units::dim<boost::units::time_base_dimension, boost::units::static_rational<1l> >, boost::units::dimensionless_type>, boost::units::heterogeneous_system<boost::units::heterogeneous_system_impl<boost::units::list<boost::units::heterogeneous_system_dim<boost::units::scaled_base_unit<boost::units::si::second_base_unit, boost::units::scale<60l, boost::units::static_rational<2l> > >, boost::units::static_rational<1l> >, boost::units::dimensionless_type>, boost::units::list<boost::units::dim<boost::units::time_base_dimension, boost::units::static_rational<1l> >, boost::units::dimensionless_type>, boost::units::dimensionless_type> >, void> >::type {aka boost::units::quantity<boost::units::unit<boost::units::list<boost::units::dim<boost::units::time_base_dimension, boost::units::static_rational<1l> >, boost::units::dimensionless_type>, boost::units::heterogeneous_system<boost::units::heterogeneous_system_impl<boost::units::list<boost::units::heterogeneous_system_dim<boost::units::scaled_base_unit<boost::units::si::second_base_unit, boost::units::scale<60l, boost::units::static_rational<2l> > >, boost::units::static_rational<1l> >, boost::units::dimensionless_type>, boost::units::list<boost::units::dim<boost::units::time_base_dimension, boost::units::static_rational<1l> >, boost::units::dimensionless_type>, boost::units::dimensionless_type> >, void>, double>}’ to non-scalar type ‘boost::units::quantity<boost::units::unit<boost::units::list<boost::units::dim<boost::units::time_base_dimension, boost::units::static_rational<1l> >, boost::units::dimensionless_type>, boost::units::homogeneous_system<boost::units::list<boost::units::si::meter_base_unit, boost::units::list<boost::units::scaled_base_unit<boost::units::cgs::gram_base_unit, boost::units::scale<10l, boost::units::static_rational<3l> > >, boost::units::list<boost::units::si::second_base_unit, boost::units::list<boost::units::si::ampere_base_unit, boost::units::list<boost::units::si::kelvin_base_unit, boost::units::list<boost::units::si::mole_base_unit, boost::units::list<boost::units::si::candela_base_unit, boost::units::list<boost::units::angle::radian_base_unit, boost::units::list<boost::units::angle::steradian_base_unit, boost::units::dimensionless_type> > > > > > > > > > > >’ requested
   quantity<si::time> t = 2.0 * metric::hour_base_unit::unit_type();
                               ^

我错过了什么？

Answer 1

快速查看文档意味着unit类之间的大多数（如果不是全部）转换都是explicit（它是design decision）。因此，您可以使用direct-initiliazation而不是copy-initialization：

#include <boost/units/systems/si.hpp>
#include <boost/units/base_units/metric/hour.hpp>

int main(int argc, char **argv) {
  using namespace boost::units;
  quantity<si::time,double> xxxxxx (2.0 * metric::hour_base_unit::unit_type());
}

它有效。

this answer中解释了在您的尝试没有解释时这种情况有效的原因。

希望有所帮助。

如何将boost :: units :: metric :: hour_base_unit转换为boost :: units :: si :: time？

1 个答案: