Question

我即将完成申请。我的资产文件夹中有超过20个PDF文件，显然它们占用了相当多的空间。有没有办法可以压缩这些文件以使应用程序更小？在我的代码/整个项目中检查/降低内存消耗的其他好方法有哪些？提前感谢任何输入。

Answer 1

您可以压缩文件，然后在需要时解压缩

这是一个教程 Zip programmatically with Android
检查 java.util.zip class，它提供了zip和amp;用于压缩和解压缩的gzip功能。
您还可以在安装应用程序后从其他站点下载pdfs

或者这应该有效：

    /*
 * 
 * Zips a file at a location and places the resulting zip file at the toLocation
 * Example: zipFileAtPath("downloads/myfolder", "downloads/myFolder.zip");
 */

public boolean zipFileAtPath(String sourcePath, String toLocation) {
    // ArrayList<String> contentList = new ArrayList<String>();
    final int BUFFER = 2048;


    File sourceFile = new File(sourcePath);
    try {
        BufferedInputStream origin = null;
        FileOutputStream dest = new FileOutputStream(toLocation);
        ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(
                dest));
        if (sourceFile.isDirectory()) {
            zipSubFolder(out, sourceFile, sourceFile.getParent().length());
        } else {
            byte data[] = new byte[BUFFER];
            FileInputStream fi = new FileInputStream(sourcePath);
            origin = new BufferedInputStream(fi, BUFFER);
            ZipEntry entry = new ZipEntry(getLastPathComponent(sourcePath));
            out.putNextEntry(entry);
            int count;
            while ((count = origin.read(data, 0, BUFFER)) != -1) {
                out.write(data, 0, count);
            }
        }
        out.close();
    } catch (Exception e) {
        e.printStackTrace();
        return false;
    }
    return true;
}

/*
 * 
 * Zips a subfolder
 * 
 */

private void zipSubFolder(ZipOutputStream out, File folder,
        int basePathLength) throws IOException {

    final int BUFFER = 2048;

    File[] fileList = folder.listFiles();
    BufferedInputStream origin = null;
    for (File file : fileList) {
        if (file.isDirectory()) {
            zipSubFolder(out, file, basePathLength);
        } else {
            byte data[] = new byte[BUFFER];
            String unmodifiedFilePath = file.getPath();
            String relativePath = unmodifiedFilePath
                    .substring(basePathLength);
            Log.i("ZIP SUBFOLDER", "Relative Path : " + relativePath);
            FileInputStream fi = new FileInputStream(unmodifiedFilePath);
            origin = new BufferedInputStream(fi, BUFFER);
            ZipEntry entry = new ZipEntry(relativePath);
            out.putNextEntry(entry);
            int count;
            while ((count = origin.read(data, 0, BUFFER)) != -1) {
                out.write(data, 0, count);
            }
            origin.close();
        }
    }
}

/*
 * gets the last path component
 * 
 * Example: getLastPathComponent("downloads/example/fileToZip");
 * Result: "fileToZip"
 */
public String getLastPathComponent(String filePath) {
    String[] segments = filePath.split("/");
    String lastPathComponent = segments[segments.length - 1];
    return lastPathComponent;
}

压缩资源文件夹中的资源和/或文件的方法？

1 个答案: