Question

我使用PHP文件从MySQL数据库输出JSON数据。当我只拉大约50行时，我的代码工作得很好，但是我的数据库包含超过12,000行。有没有人知道如何在没有我的服务器返回＆＃34;死亡的白色屏幕的情况下提取更多数据＆＃34;？大声笑。我目前的代码如下：

<?php
    //Create Database connection
    $db = mysql_connect("localhost","username","password");
    if (!$db) {
        die('Could not connect to db: ' . mysql_error());
    }

    //Select the Database
    mysql_select_db("dbname",$db);

    //Replace * in the query with the column names.
    $result = mysql_query("select * from customer limit 50", $db);  

    //Create an array
    $json_response = array();

    while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
        $row_array['customerfname'] = $row['customerfname'];
        $row_array['customerlname'] = $row['customerlname'];
        $row_array['customeremail'] = $row['customeremail'];
        $row_array['customerphone'] = $row['customerphone'];
        $row_array['customercity'] = $row['customercity'];
        $row_array['customeraddress'] = $row['customeraddress'];
        $row_array['lastupdate'] = $row['lastupdate'];
        //push the values in the array
        array_push($json_response,$row_array);
    }
    echo json_encode($json_response);

    //Close the database connection
    fclose($db);

?>

Answer 1

如果前50行进展顺利，问题可能出在数据上...... 我认为是恶意单引号或其他什么

您可以使用限制来尝试不同的数据集。例如，如果你想检查下一个50并跳过前50个限制

$result = mysql_query("select * from customer limit 50, 50", $db);

我认为你应该尝试1到50，50到100的集合，然后缩小到下一个10并找出哪个集合然后哪个行/记录给出问题然后找出解决问题的json编码问题区域。

Answer 2

您可以根据GET / POST参数输出json数据，方法是在sql表中对结果进行分页。例如，如果你想要从第50到第100行，你可以做这样的事情：

<?php
    //Create Database connection
    $mysqli = new mysqli("localhost", "username", "password", "dbname");
    if ($mysqli->connect_errno) {
        die('Could not connect to db: ' . $mysqli->connect_error);
    }

    // Get the page we are interested in
    $page = $_REQUEST['page']; // E.g. 1

    //Replace * in the query with the column names.
    $result = $mysqli->query("SELECT * FROM customer LIMIT ".(50*$page).",50");

    //Create an array
    $json_response = array();

    while ($row = $result->fetch_assoc()) {
        //push the values in the array
        array_push($json_response,$row);
    }
    echo json_encode($json_response);

    // free result set
    $result->close();

    //Close the database connection
    $mysqli->close();
?>

使用PHP输出JSON数据，当调用太多行时，我得到“白屏死机”

2 个答案: