我可以在Linux上的Makefile中设置PATH但不能在Mac OS X中设置PATH。使用OS X时,PATH会被设置但不会被使用。这是一个示范:
在CentOS 6上使用bash 4.1.2(1)-release和GNU Make 3.81
$ pwd
/tmp/experiment
$ find * -type f -ls
132133 4 -rw-rw-r-- 1 tlim tlim 113 Aug 26 11:01 Makefile
132132 4 -rwxrwxr-x 1 tlim tlim 28 Aug 26 10:59 bin/myprog
$ cat Makefile
export PATH := $(shell /bin/pwd)/bin:$(PATH)
what:
@echo PATH=$$PATH
@echo PATH=$(PATH)
which myprog
myprog
$ cat bin/myprog
#!/bin/bash
echo HERE I AM.
$ make what
PATH=/tmp/experiment/bin:/usr/stack/bin:/usr/lib64/qt-3.3/bin:/usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin
PATH=/tmp/experiment/bin:/usr/stack/bin:/usr/lib64/qt-3.3/bin:/usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin
which myprog
/tmp/experiment/bin/myprog
myprog
HERE I AM.
这里使用GNU Make 3.81在Mac OS X 10.9.4上运行完全相同的文件:
$ pwd
/tmp/experiment
$ find * -type f -ls
51838886 8 -rw-rw-r-- 1 tal wheel 113 Aug 26 07:01 Makefile
51838887 8 -rwxrwxr-x 1 tal wheel 28 Aug 26 06:59 bin/myprog
$ cat Makefile
export PATH := $(shell /bin/pwd)/bin:$(PATH)
what:
@echo PATH=$$PATH
@echo PATH=$(PATH)
which myprog
myprog
$ cat bin/myprog
#!/bin/bash
echo HERE I AM.
$ make what
PATH=/tmp/experiment/bin:/Users/tal/bin:/opt/local/sbin:/opt/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/opt/X11/bin
PATH=/tmp/experiment/bin:/Users/tal/bin:/opt/local/sbin:/opt/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/opt/X11/bin
which myprog
/tmp/experiment/bin/myprog
myprog
make: myprog: No such file or directory
make: *** [what] Error 1
如您所见,PATH正在设置并导出到环境中。两个" echo $ PATH"和#34; myprog"显示路径已设置。但是,当运行" myprog" shell无法找到它。
更新:如果我将这两行添加到Makefile中的what
配方:
@echo SHELL=$$SHELL
@echo SHELL=$(SHELL)
Linux和Mac输出:
SHELL=/bin/bash
SHELL=/bin/sh
在运行SHELL
之前,两者都在/bin/bash
等于make
。这让我觉得在Makefile中设置SHELL
只是神奇的,并且是GNU制作手册总是设置SHELL
的众多原因之一。
答案 0 :(得分:5)
事实证明,PATH变量是特殊的,除非"SHELL" is also set,否则不会导出。换句话说,如果我将这一行添加到Makefile中,它可以在Mac和Linux上运行:
SHELL=/bin/bash
这当然让我想知道为什么Mac会有所不同。希望通过记录这一点,其他人看到这个问题也将受益。另外,我想知道为什么Mac会有所不同,如果确实如此。