Question

我尝试使用以下代码导出csv，xls，txt和amp;来自mysql数据库的xml文件。

<?php
    include("includes/config.php"); 

    if($_POST["frmDownloadFiles"]){ 
        $output = "";
        $line_termineted="\n";

        if( $_POST["frmDownloadFiles"] =="CSV") {
            $field_termineted= ","; 
        }
        if( $_POST["frmDownloadFiles"] =="XLS") {
            $field_termineted= "\t"; 
        }
        if ($_POST["frmDownloadFiles"] =="TXT") {
            $field_terminated= "    ";
        } 
        if ($_POST["frmDownloadFiles"] =="XML") {
            $field_terminated= "\t";
        }
        $enclosed='';
        $escaped="\\";

        $export_schema = "Name".$field_termineted."Code".$field_termineted."Email".$field_termineted."Designation".$field_termineted."Salary";
        $dataQuery = doSelectCsv();
        //$handle = fopen($dataQuery, "w+");
//      while ($strBookData = fputcsv($handle, 10000, ",")) {       //  To get Array from CSV
//            $strDatas[] = $strBookData;
//        }
//      printArray($strDatas); exit;
        $strDatas = array();
        $strDatas = $dataQuery;
        //printArray($strDatas); exit;  
        $output.= $export_schema;
        //printArray($field_termineted);
        $p=0;
        for($k=0; $k<count($strDatas); $k++) {
            $p++;
            if( $_POST["frmDownloadFiles"] =="CSV") {
                $output.= $line_termineted;
            }
            if( $_POST["frmDownloadFiles"] =="XLS") {
                $output.= $line_termineted;
            }
            if( $_POST["frmDownloadFiles"] =="TXT") {
                $output.= $line_termineted;
            }
            echo "<employee_details>"; 
            if( $_POST["frmDownloadFiles"] =="XML") {
                echo "<Row>"; 
                echo "<name>" . $strDatas[$k]['0'] . "</name>";
                echo "<code>" . $strDatas[$k]['1'] . "</code>";
                echo "<mail>" . $strDatas[$k]['2'] . "</mail>";
                echo "<designation>" . $strDatas[$k]['3'] . "</designation>";
                echo "<salary>" . $strDatas[$k]['4'] . "</salary>"; 
                echo "</Row>";
            }
            echo "</employee_details>";
            $output.=$enclosed.$strDatas[$k]['0'].$enclosed.$field_termineted;
            $output.=$enclosed.$strDatas[$k]['1'].$enclosed.$field_termineted;
            $output.=$enclosed.$strDatas[$k]['2'].$enclosed.$field_termineted;
            $output.=$enclosed.$strDatas[$k]['3'].$enclosed.$field_termineted;
            $output.=$enclosed.$strDatas[$k]['4'].$enclosed.$field_termineted;
        }

        header("Content-Description: File Transfer");
        if( $_POST["frmDownloadFiles"] =="CSV"){
            header("Content-Type: application/csv");
            header("Content-Disposition: attachment; filename=report".date("d_m_Y_H_i_s").".csv");
        } 
        if( $_POST["frmDownloadFiles"] =="XLS") {
            header("Content-Type: application/vnd.ms-excel");
            header("Content-disposition: attachment; filename=report".date("d_m_Y_H_i_s").".xls");
        }
        if( $_POST["frmDownloadFiles"] =="TXT") {
            header("Content-Type: application/txt");
            header("Content-disposition: attachment; filename=report".date("d_m_Y_H_i_s").".txt");
        }
        if( $_POST["frmDownloadFiles"] =="XML") {
            header("Content-Type: application/xml");
            header("Content-disposition: attachment; filename=report".date("d_m_Y_H_i_s").".xml");
        }

        header("Content-Transfer-Encoding: binary");
        header("Expires: 0");
        header("Cache-Control: must-revalidate");
        header("Pragma: public");
        header("Content-Length: ".strlen($output));
        ob_clean();
        flush();
        echo $output;
        exit;
    }
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Export Files</title>
<link href="css/export.css" rel="stylesheet" type="text/css"/>
</head>

<body>
<form id="frmEmployee" name="frmEmployee" enctype="multipart/form-data" method="post" action="" onsubmit="return validation();">
<div class="all">
<div class="alls">
  <div class="main">
    <div class="inner">
      <div class="top">
        <p>&nbsp;</p>
        <div class="text" align="center">
          <p class="det">DOWNLOAD FILES</p>
        </div>
        <p>&nbsp;</p>
      </div>
      <p>&nbsp;</p>
      <p>&nbsp;</p>
      <div class="nnn">
        <div class="name">Download CSV file:</div>
        <div class="field">
          <label>
          <input type="submit" name="frmDownloadFiles" id="frmDownloadFiles" value="CSV" class="subb" />
          </label>
        </div>
        <p>&nbsp;</p>
      </div>
      <p>&nbsp;</p>
      <div class="nnn">
        <div class="name">Download excel file:</div>
        <div class="field">
          <label>
          <input type="submit" name="frmDownloadFiles" id="frmDownloadFiles" value="XLS" class="subb" />
          </label>
        </div>
        <p>&nbsp;</p>
      </div>
      <p>&nbsp;</p>
      <div class="nnn">
        <div class="name">Download text file:</div>
        <div class="field">
          <label>
          <input type="submit" name="frmDownloadFiles" id="frmDownloadFiles" value="TXT" class="subb" />
          </label>
        </div>
        <p>&nbsp;</p>
      </div>
      <p>&nbsp;</p>
      <div class="nnn">
        <div class="name">Download xml file:</div>
        <div class="field">
          <label>
          <input type="submit" name="frmDownloadFiles" id="frmDownloadFiles" value="XML" class="subb" />
          </label>
        </div>
        <p>&nbsp;</p>
      </div>
      </div>
    <p>&nbsp;</p>
    </div>
</div>
  </div>
  </form>
</body>
</html>

前三个工作正常，但xml无法从数据库导出。请找我的错误并帮助我。提前致谢

Answer 1

这是因为对于除XML之外的其他方法，您将结果存储在$output变量（最后打印的变量）中。但是对于XML格式，您只需回显结果（例如，不使用$ouput .= '<Row>'）。

在任何先前输出之前使用PHP中的header函数（例如，由echo生成）。替换你的：

echo "<employee_details>"; 
if( $_POST["frmDownloadFiles"] =="XML") {
    echo "<Row>"; 
    echo "<name>" . $strDatas[$k]['0'] . "</name>";
    echo "<code>" . $strDatas[$k]['1'] . "</code>";
    echo "<mail>" . $strDatas[$k]['2'] . "</mail>";
    echo "<designation>" . $strDatas[$k]['3'] . "</designation>";
    echo "<salary>" . $strDatas[$k]['4'] . "</salary>"; 
    echo "</Row>";
 }
 echo "</employee_details>";

使用

$output .= "<employee_details>";
if( $_POST["frmDownloadFiles"] =="XML") {
    $output .= "<Row>";
    $output .= "<name>" . $strDatas[$k]['0'] . "</name>";
    $output .= "<code>" . $strDatas[$k]['1'] . "</code>";
    $output .= "<mail>" . $strDatas[$k]['2'] . "</mail>";
    $output .= "<designation>" . $strDatas[$k]['3'] . "</designation>";
    $output .= "<salary>" . $strDatas[$k]['4'] . "</salary>";
    $output .= "</Row>";
}
$output .= "</employee_details>";

Answer 2

使用php从xml导出mysql数据，试试这段代码：

<?php
$dbh=mysql_connect($localhost, $username, $password) or die ('I cannot connect to the database because: ' . mysql_error());
$result = mysql_query("SELECT * FROM 12345_flv.flv WHERE enabled = '1' ORDER BY id DESC") or die('Could not connect: ' . mysql_error());  

$string = '<videos><updated>2010-07-20T00:00:00Z</updated><video>';

while ($row = mysql_fetch_array($result)) { 
    $id=$row['id'];
    $title=$row['title'];
    $string .='<id>'.$id.'</id>';
    $string .='<title>'.$title.'</title>';
}
$string .='</video></videos>'; 
$xml = new SimpleXMLElement($string);
Header('Content-type: text/xml');
echo $xml->asXML();
?>

使用php从数据库导出xml文件

2 个答案: