Question

好的我想在这里学习我是菜鸟，基本上，这是我当前的（ server.php ）代码，

<?php
/**
 * Sample php server script for a wookmark integration
 *
 * @author Sebastian Helzle <sebastian@helzle.net>
 */

/**
 * Basic class which provides all functions to retrieve and paginate pictures
 */
class PictureDatabase {

  /**
   * @var array $data
   */
  protected $data;

  /**
   * @var int $itemsPerPage
   */
  protected $itemsPerPage;

  function __construct($data, $itemsPerPage) {
    $this->data = $data;
    $this->itemsPerPage = $itemsPerPage;
  }

  /**
   * Returns the pictures of the given page or an empty array if page doesn't exist
   * @param int $page
   * @return array
   */
  public function getPage($page=1) {
    if ($page > 0 && $page <= $this->getNumberOfPages()) {
      $startOffset = ($page - 1) * $this->itemsPerPage;
      return array_slice($this->data, $startOffset, $this->itemsPerPage);
    }
    return array();
  }

  /**
   * Returns the maximum number of pages
   * @return int
   */
  public function getNumberOfPages() {
    return ceil(count($this->data) / $this->itemsPerPage);
  }
}

// Our data source
$data = include ('xyz.php');





// Make data array a bit bigger to have more pages
for ($i=0; $i<3; $i++) {
  $data = array_merge($data, $data);
}

// Create instance of picture database with 10 items per page and our data as source
$pictureDatabase = new PictureDatabase($data, 10);

$result = array(
  'success' => TRUE,
  'message' => 'Retrieved pictures',
  'data' => array()
);

$callback = isset($_REQUEST['callback']) ? $_REQUEST['callback'] : false;

// Get requested page number from request and return error message if parameter is not a number
$page = 1;
try {
  $page = intval($_REQUEST['page']);
} catch (Exception $e) {
  $result['success'] = FALSE;
  $result['message'] = 'Parameter page is not a number';
}

// Get data from database
$result['data'] = $pictureDatabase->getPage($page);

if (count($result['data']) == 0 || $page >= $pictureDatabase->getNumberOfPages()) {
  $result['success'] = TRUE;
  $result['message'] = 'No more pictures';
}

// Encode data as json or jsonp and return it
if ($callback) {
  header('Content-Type: application/javascript');
  echo $callback.'('.json_encode($result).')';
} else {
  header('Content-Type: application/json');
  echo json_encode($result);
}

好吧现在在// datasource下，原来是

$data = array (
array (
'id' => "1",
'title' => "First image",
'url' => "http://www.example.org/1",
'width' => "200",
'height' => "283",
'image' => "/images/image_1_big.jpg",
'preview' => "/images/image_1.jpg"
),
array (
'id' => "2",
'title' => "Second image",
'url' => "http://www.example.org/2",
'width' => "200",
'height' => "300",
'image' => "/images/image_2_big.jpg",
'preview' => "/images/image_2.jpg"
)
);

现在我在这里很少有人的帮助下得到另一个（ xyz.php ）文件从sql打印出来，

<?php
// Our data source
$conn = mysql_connect("", "", "");

if (!$conn) {
    echo "Unable to connect to DB: " . mysql_error();
    exit;
}

if (!mysql_select_db("")) {
    echo "Unable to select mydbname: " . mysql_error();
    exit;
}
//= Query ========================//
$sql = mysql_query("select id, title, url, width, height, image, preview from mmf_content");

//= Closed while ====================//
/*everytime it fetches the row, adds it to array...*/
$foo = "array (\n";
while ($row=mysql_fetch_assoc($sql)){
    $foo.= "array (\n";
    foreach ($row as $key => $value){
        $foo .= "'{$key}' => \"{$value}\",\n";
    }
    $foo = substr($foo,0,strlen($foo)-2)."\n";//removes the comma at the end
    $foo .="),\n";
}
$foo = substr($foo,0,strlen($foo)-2)."\n";//removes the comma at the end
$foo .= ');';
echo '<pre>'.$foo.'</pre>';
?>

这是打印输出，

array (
array (
'id' => "1",
'title' => "First image",
'url' => "http://www.example.org/1",
'width' => "200",
'height' => "283",
'image' => "/images/image_1_big.jpg",
'preview' => "/images/image_1.jpg"
),
array (
'id' => "2",
'title' => "Second image",
'url' => "http://www.example.org/2",
'width' => "200",
'height' => "300",
'image' => "/images/image_2_big.jpg",
'preview' => "/images/image_2.jpg"
)
);

现在当前在server.php中

// Our data source
$data = include ('xyz.php');

它不起作用，但如果我手动放置打印输出它可以很好地工作。

所以如何让$ data =打印输出xyz.php

Answer 1

更改

$foo = "array (\n";
while ($row=mysql_fetch_assoc($sql)){
    $foo.= "array (\n";
    foreach ($row as $key => $value){
        $foo .= "'{$key}' => \"{$value}\",\n";
    }
    $foo = substr($foo,0,strlen($foo)-2)."\n";//removes the comma at the end
    $foo .="),\n";
}
$foo = substr($foo,0,strlen($foo)-2)."\n";//removes the comma at the end
$foo .= ');';
echo '<pre>'.$foo.'</pre>';

到

$foo = array();
while ($row=mysql_fetch_assoc($sql)){
    $foo[]= $row;
}
return $foo;

Answer 2

如果您包含xyz.php，您将可以访问内部的所有内容，因此无需返回任何内容。把它放在xyz.php中：

$data = array();
while ($row=mysql_fetch_assoc($sql)){
    $data[]= $row;
}

然后在server.php内部，您将能够访问$ data。

在另一个php文件中使用php printout

2 个答案: