Question

我在AsyncTask innerc类中创建以下方法以连接到Internet并从提供的URL获取JSON文件。如果连接错误，我遇到问题，我的应用程序会挂起很长时间等待连接......

        private JSONArray connectAndCreateJsonArray(String url) {
            JSONArray jsonArray = new JSONArray();

            try {
                HttpClient client = new DefaultHttpClient();
                HttpGet request = new HttpGet(url);
                request.addHeader("Cache-Control", "no-cache");
                HttpResponse response = client.execute(request);
                HttpEntity entity = response.getEntity();

                InputStreamReader in = new InputStreamReader(entity.getContent());
                BufferedReader reader = new BufferedReader(in);
                StringBuilder stringBuilder = new StringBuilder();
                String line = "";
                while ((line = reader.readLine()) != null) {
                    stringBuilder.append(line);
                }

                jsonArray = new JSONArray(stringBuilder.toString());

            } catch (IllegalStateException e) {
                e.printStackTrace();                
            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            return jsonArray;
        }

我从doInBackground（）方法调用此方法。如何使用AlertDialog处理连接超时？

Answer 1

HttpGet httpGet = new HttpGet(url);
HttpParams httpParameters = new BasicHttpParams();

TimeOut，直到建立连接

int timeOutInMillis = 10*1000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeOutInMillis);

设置timeOut直到收到数据

int socketTimeOutinMillis = 5000;
HttpConnectionParams.setSoTimeout(httpParameters, socketTimeOutinMillis);

使用参数

创建客户端

DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
HttpResponse response = httpClient.execute(httpGet);

Answer 2

我猜你试图在你的主线程上连接互联网，导致你的应用程序挂起。为您的连接生成一个单独的线程。您可以捕获超时异常并在相应的catch块中显示toast或alertdialog

catch（TimeoutException e）{

      String error = e.getMessage();    
        e.printStackTrace();  
         boolean errorflag=true;      
      return error ;

在postexecute中显示用户此异常

如何设置连接超时并为其添加AlertDialog

2 个答案: