Question

我是Linux和bash的新手。我从Iperf网络性能和吞吐量工具中捕获了文件。文件很大，所以我没有附上它。但它看起来像这样：

bin/iperf.exe -s -P 0 -i 1 -p 5001 -w 8192.0K -N -f m
------------------------------------------------------------
Server listening on TCP port 5001
TCP window size: 8.00 MByte
------------------------------------------------------------
[148] local 192.168.0.14 port 5001 connected with 192.168.0.12 port 49504
[260] local 192.168.0.14 port 5001 connected with 192.168.0.12 port 49501
[276] local 192.168.0.14 port 5001 connected with 192.168.0.12 port 49502
[292] local 192.168.0.14 port 5001 connected with 192.168.0.12 port 49503
[ ID] Interval       Transfer     Bandwidth
[148]  0.0- 1.0 sec  0.00 MBytes  0.00 Mbits/sec
[148]  1.0- 2.0 sec  0.00 MBytes  0.00 Mbits/sec
[148]  2.0- 3.0 sec  0.01 MBytes  0.07 Mbits/sec
[276]  0.0- 1.0 sec  2.67 MBytes  22.4 Mbits/sec
[SUM]  0.0- 3.0 sec  2.68 MBytes  7.49 Mbits/sec
[292]  0.0- 1.0 sec  3.21 MBytes  26.9 Mbits/sec
[148]  3.0- 4.0 sec  1.75 MBytes  14.7 Mbits/sec
[260]  0.0- 1.0 sec  1.86 MBytes  15.6 Mbits/sec
[292]  1.0- 2.0 sec  5.08 MBytes  42.6 Mbits/sec
[SUM]  0.0- 4.0 sec  11.9 MBytes  25.0 Mbits/sec
[148]  4.0- 5.0 sec  1.10 MBytes  9.25 Mbits/sec
[276]  1.0- 2.0 sec  2.59 MBytes  21.7 Mbits/sec
[260]  1.0- 2.0 sec  1.21 MBytes  10.2 Mbits/sec
[292]  2.0- 3.0 sec  1.65 MBytes  13.9 Mbits/sec
[SUM]  1.0- 5.0 sec  6.56 MBytes  13.8 Mbits/sec
[260]  2.0- 3.0 sec  1.97 MBytes  16.5 Mbits/sec
[276]  2.0- 3.0 sec  3.42 MBytes  28.7 Mbits/sec
[148]  5.0- 6.0 sec  1.81 MBytes  15.2 Mbits/sec
[260]  3.0- 4.0 sec  2.09 MBytes  17.5 Mbits/sec
[SUM]  2.0- 6.0 sec  9.29 MBytes  19.5 Mbits/sec

然后我们有类似模式的大量数据。我想找到最高和最低的＆＃34; Mbits / sec＆＃34;来自文件的值。此文件可以保存为.txt或.csv（如果有帮助）。我尝试过某种类型和awk过滤器实验，但直到现在还没有用。

我试过的排序过滤器是

Answer 1

这样的事情会起作用：

awk '/^\[SUM]/ { 
    min = !min || $7 < min ? $7 : min
    max = $7 > max ? $7 : max 
} END { print "min:", min, "max:", max }' file

当[SUM]在行的开头匹配时，如有必要，使用三元运算符覆盖最小值和最大值。处理完文件后，打印最小值和最大值。

输出：

min: 7.49 max: 25.0

如何从4列文本文件中过滤最大和最小的数字

1 个答案: