为什么sys.excepthook不起作用?

时间:2014-08-25 22:00:59

标签: python sys

如果我尝试执行此代码,为什么不调用sys.excepthook函数?

import sys;
def MyExcepthook(ex_cls, ex, tb):

    print("Oops! There's an Error.\n");

    a=open("./ERR.txt","w"); #Fixed as suggested by unutbu BUT the problem is the same!
    a.write("Oops! There's an Error.\n");
    a.close();

sys.excepthook = MyExcepthook;

def main():
    print(1/0);

if (__name__=="__main__"):
    main();

输出:

Traceback (most recent call last):
  File "C:\Users\Path\to\my\python\file.py", line 13, in <module>
    main();
  File "C:\Users\Path\to\my\python\file.py", line 10, in main
    print(1/0);
ZeroDivisionError: division by zero

预期输出(print):

Oops! There's an Error.

应创建一个新文件(Err.txt)(open

print函数未显示文本且未创建文件,因为未调用sys.excepthook函数 - 为什么?

- &gt;编辑 我的问题是由idle-python 3.4中的一个错误引起的,因为现在我试图通过解释器python(命令行)运行代码并且它可以工作!如果不在idle-python 3.4中警告这个错误,这使得我的问题毫无用处。对不起,谢谢你的帮助!

[解决方案] 如果有人有同样的问题=&gt;尝试通过命令行运行您的代码!而不是来自IDE。

1 个答案:

答案 0 :(得分:3)

您的自定义异常错误本身不得引发异常:

a=open("./ERR.txt")   # opens the file in read mode

应该是

a=open("./ERR.txt", 'w')  # open the file in write mode.

当自定义excepthook引发异常时,您应该看到

之类的东西
Oops! There's an Error.

Error in sys.excepthook:
...
IOError: [Errno 2] No such file or directory: './ERR.txt'

Original exception was:
...
ZeroDivisionError: integer division or modulo by zero

PS。不要忘记删除所有那些不必要的分号!

import sys
def my_excepthook(ex_cls, ex, tb):
    msg = "Oops! There's an Error.\n"
    print(msg)

    with open("./ERR.txt", 'w') as a:
        a.write(msg)

sys.excepthook = my_excepthook

def main():
    print(1/0)

if __name__=="__main__":
    main()