Question

在一个人的Details视图中，我还要显示DbContext中的其他对象，表Survey的每个记录都是准确的。所以我将它们插入ViewBag

人的控制者行动：

   [HttpPost]
        public ActionResult _Survey1(int id) {
            System.Diagnostics.Debug.WriteLine("PASSED ID: " + id);
            Person person = db.Persons.Find(id);
            ViewBag.Surveys = db.Surveys.ToList();//HERE I insert Surveys to ViewBag
            return PartialView(person);
        }

并尝试在View中迭代它们：

@model WebApplication2.Models.Person
<hr />
<h2>Survey</h2>

<input type="button" id="Coll" value="Collapse" onclick="javascript:CollapseDiv()" />
<p>
    @Html.DisplayFor(x => ViewBag.Surveys.Count)
</p>
@foreach (var survey in ViewBag.Surveys) {
    <p>
        @using (Html.BeginForm()) {

            <text>ANK</text>
            @Html.DisplayFor(x => survey.Questions.Count)
            @Html.EditorFor(x => survey.Questions) 
            <input type="submit" />
        }
    </p>
}

<hr />

问题是我得到了：

enter image description here

问题：由于tschmit007建议如何定义可以采用Person和`IEnumerable并将数据传递给它的模型？

Answer 1

定义包含Person和Surveys属性的视图模型。例如

public class MyViewModel
{
  public Person Person { get; set; } // or create properties for each property or Person
  public IEnumerable<Survey> Surveys { get; set; }
}

显示页面时

[HttpGet]
public ActionResult Details (int ID)
{
  MyViewModel model = new MyViewModel();
  model.Person = db.Persons.Find(id);
  model.Surveys = db.Surveys;
  return View(model);
}

并在视图中

@model YourAssembly.MyViewModel

@Html.DisplayFor(m => m.Person.SomeProperty) // display properties of person

@foreach (var survey in Model.Surveys) {
  @using (Html.BeginForm()) {
        @Html.EditorFor(x => survey.Questions) 
        <input type="submit" />
  }
}

Answer 2

我在没有创建ViewModel的情况下将数据作为元组传递。元组出现在.NET 4.0中。这完成了这项工作：

 public ActionResult _Survey1(int id) {
            System.Diagnostics.Debug.WriteLine("PASSED ID: " + id);
            Person person = db.Persons.Find(id);
            var tuple = new Tuple<Person,  List<Survey>>(person, db.Surveys.ToList()){};               
            return PartialView(tuple);
        }

@using WebApplication2.Models
@model   System.Tuple<Person, List<Survey>>

<hr />
<h2>Surveys</h2>

<input type="button" id="Coll" value="Collapse" onclick="javascript:CollapseDiv()" />
<p>
    @Html.DisplayFor(x => Model.Item2.Count)
</p>

@foreach (var survey in Model.Item2) {
    using (Html.BeginForm()) {
        <text>Number of Questions in a Survey</text>
        @Html.DisplayFor(x => survey.Questions.Count)
        <p/>
        @Html.EditorFor(x => survey.Questions)
        <input type="submit" />
    }

}
<hr />

Answer 3

@Html.DisplayFor(x => ViewBag.Surveys.Count)希望您使用模型的一部分ViewBag应为x。您需要做的是删除For，这使得它不使用模型。

改为使用：

@Html.Display(ViewBag.Surveys.Count) 

@Html.Display(survey.Questions.Count)
@Html.Editor(survey.Questions)

Display最有可能被排除在外：

<p>@ViewBag.Surveys.Count</p>

也会奏效。

如何将两个不同类的对象传递给View模型

3 个答案: