Question

我将此代码写入我的图像animate：

protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        requestWindowFeature(Window.FEATURE_NO_TITLE);
        getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN,
                WindowManager.LayoutParams.FLAG_FULLSCREEN);
        setContentView(R.layout.activity_main);
        ImageView img=(ImageView) findViewById(R.id.backImage);
        ImageView img2=(ImageView) findViewById(R.id.upImage);
        animBounce=AnimationUtils.loadAnimation(getApplicationContext(), R.anim.bounce);
        animBounce.setAnimationListener(this);

        img.setVisibility(View.VISIBLE);
        img.setAnimation(animBounce);

        img2.setAnimation(animBounce);

    }

我在xml文件中有两个imageView，imageView1名称backImage和xml文件中的imageView2名称upImage。
我想img开始动画，并在1000ms img2开始动画，但在这个我的代码img和img2同时开始。
如何解决这个问题？

Answer 1

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    requestWindowFeature(Window.FEATURE_NO_TITLE);
    getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN,
            WindowManager.LayoutParams.FLAG_FULLSCREEN);
    setContentView(R.layout.activity_main);
    ImageView img=(ImageView) findViewById(R.id.backImage);
    ImageView img2=(ImageView) findViewById(R.id.upImage);
    animBounce=AnimationUtils.loadAnimation(getApplicationContext(), R.anim.bounce);
    animBounce.setAnimationListener(this);

    img.setVisibility(View.VISIBLE);
    img.setAnimation(animBounce);

    final Handler handler = new Handler();
    handler.postDelayed(new Runnable() {
        @Override
        public void run() {
            img2.setAnimation(animBounce); 
        }
    }, 1000);
}

将其添加到onCreate方法的末尾。我希望它有所帮助。

Android imageView1启动动画，1000ms后启动imageView2

1 个答案: