Question

declare @x xml = '<XML> <UNSTRING STATEMENTNUMBER="48515">
          <STRING>CRD001M-OPTIONI</STRING>
          <DELIMITERS>
            <DELIMITER>aaa</DELIMITER>
          </DELIMITERS>
          <SUBSTRINGS>WS-MENU-STACK1 WS-MENU-STACK2 WS-MENU-STACK3 WS-MENU-STACK4 WS-MENU-STACK5 WS-MENU-STACK6 WS-MENU-STACK7 WS-MENU-STACK8 WS-MENU-STACK9 WS-MENU-STACK10 TALLYING IN WS-MENU-STACK-TALLY</SUBSTRINGS>
          <DELIMITERSFOUND>
            <DELIMITER>
            </DELIMITER>
          </DELIMITERSFOUND>
          <INDICES>
            <INDEX>
            </INDEX>
          </INDICES>
          <POINTER>
          </POINTER>
          <TALLYING>
          </TALLYING>
          <ONOVERFLOW>
          </ONOVERFLOW>
        </UNSTRING></XML>'

在上面的XML标签中有空间隔离的值我想在下面的字符串下面做

declare @x xml = '<XML> <UNSTRING STATEMENTNUMBER="48515">
          <STRING>CRD001M-OPTIONI</STRING>
          <DELIMITERS>
            <DELIMITER>aaa</DELIMITER>
          </DELIMITERS>
            <SUBSTRINGS>WS-MENU-STACK1</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK2</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK3</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK4</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK5</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK6</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK7</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK8</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK9</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK10</SUBSTRINGS>
            <SUBSTRINGS>TALLYING</SUBSTRINGS>
            <SUBSTRINGS>IN</SUBSTRINGS>
            <SUBSTRINGS>WS-MENU-STACK-TALLY</SUBSTRINGS>
          <DELIMITERSFOUND>
            <DELIMITER>
            </DELIMITER>
          </DELIMITERSFOUND>
          <INDICES>
            <INDEX>
            </INDEX>
          </INDICES>
          <POINTER>
          </POINTER>
          <TALLYING>
          </TALLYING>
          <ONOVERFLOW>
          </ONOVERFLOW>
        </UNSTRING></XML>'

请帮助我在这里如何通过替换或任何其他事情解决问题我使用了替换功能，但无法找到值此处<substrings>标记值按空格隔离，因此查找每个值都在<substrings> value </substrings>之间

Answer 1

使用以下查询并享受它的结果：

declare @x xml = '<XML> <UNSTRING STATEMENTNUMBER="48515">
          <STRING>CRD001M-OPTIONI</STRING>
          <DELIMITERS>
            <DELIMITER>aaa</DELIMITER>
          </DELIMITERS>
          <SUBSTRINGS>WS-MENU-STACK1 WS-MENU-STACK2 WS-MENU-STACK3 WS-MENU-STACK4 WS-MENU-STACK5 WS-MENU-STACK6 WS-MENU-STACK7 WS-MENU-STACK8 WS-MENU-STACK9 WS-MENU-STACK10 TALLYING IN WS-MENU-STACK-TALLY</SUBSTRINGS>
          <DELIMITERSFOUND>
            <DELIMITER>
            </DELIMITER>
          </DELIMITERSFOUND>
          <INDICES>
            <INDEX>
            </INDEX>
          </INDICES>
          <POINTER>
          </POINTER>
          <TALLYING>
          </TALLYING>
          <ONOVERFLOW>
          </ONOVERFLOW>
        </UNSTRING></XML>'

DECLARE @T NVARCHAR(MAX) = CAST(@X AS NVARCHAR(MAX))
SELECT CAST(
            REPLACE(@T,
                    '<SUBSTRINGS>'+D.value('.','VARCHAR(max)')+'</SUBSTRINGS>',
                    '<SUBSTRINGS>'+REPLACE(D.value('.','VARCHAR(max)'),' ','</SUBSTRINGS><SUBSTRINGS>')+'</SUBSTRINGS>'
                    )
        AS XML)
FROM @x.nodes('/XML/UNSTRING/SUBSTRINGS') X(D)

如何通过删除空格来查找标记值

1 个答案: