碎片onCreateView被称为两次android

Question

我正在使用viewPage，FragmentManager和Fragment。 FragmentManager中有一个switch case来初始化每个片段。但我的片段onCreateView在我的应用程序第一次进入前景时被调用了两次。我正在附加FragmentManager类以及片段的onCreateView方法代码。请告诉我我是否做错了。

下面的

是我的fragmentManager类

public class TabsPagerAdapter extends FragmentPagerAdapter {

    public TabsPagerAdapter(FragmentManager fm) {
        super(fm);
    }

    @Override
    public Fragment getItem(int index) {

        switch (index) {

        case 0:
            //Home fragment activity
            System.out.println("fragment case 0");
            return new LatestFragment();
        case 1:
            // Pages fragment activity
            System.out.println("fragment case 1");
            return new MostDownloadFragment();
        case 2:
            // Photos fragment activity
            System.out.println("fragment case 2");
            return new BestFragment();
        case 3:
            // WhatsHot fragment activity
            System.out.println("fragment case 3");
            return new FavouriteFragment();

        default:
            break;
        }

        return null;
    }

    @Override
    public int getCount() {
        // get item count - equal to number of tabs
        return 4;
    }
}

及以下是onCreateView of fragment

public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {

        View rootView = inflater.inflate(R.layout.fragment_latest, container, false);
        gridView = (GridView)rootView.findViewById(R.id.grid_view);


        context=getActivity().getApplicationContext();
        adapter = new ImageAdapter();

        if (TabsArraylistData.al_latest.size() == 0) {
            System.out.println("fragment latest if");
            new GetCategoryAsynTask().execute();
        }else {
            System.out.println("fragment latest else");
            gridView.setAdapter(adapter);
        }

        return rootView;
    } // onCreateView -----------------------------------------------------

我的问题是System.out.println（＆＃34;片段最新如果＆＃34;）;正在打印两次