Question

我是SQL的新手所以原谅任何新手的错误......

每周，用户都会回答10个问题，我会跟踪他们的进展情况。对于每个用户，我想找到正确回答问题的总分，按周显示。所以结果看起来像这样：

userID = 1

weekID = 3

TotalPoints = 5

以下是我的专栏：

userID，weekID，
QuestionA，QuestionA_ID，A_Correct，PointsA
QuestionB，QuestionB_ID，B_Correct，PointsB
TotalPoints （PointsA + PointsB）

以下是我的问题：

SELECT userID, weekID, 
SUM(DISTINCT PointsA + PointsB) as TotalPoints
FROM Results [LIMIT 0,3],
    (SELECT SUM(DISTINCT PointsA)
    FROM Results
    WHERE A_Correct = "Y" and userID = "1"),

    (SELECT SUM(DISTINCT PointsB)
    FROM Results
    WHERE B_Correct = "Y" and userID = "1")
WHERE userID = "1" and weekID < "10"
GROUP BY weekID ORDER BY weekID ASC;

好像我从每周都得到总计的总数而不是每周的总数。关于我哪里出错的任何想法？如何更好地做到这一点？提前谢谢。

Answer 1

我想你想要这样的东西：

select userID, weekID,
       sum(case when A_Correct = 'Y' then PointsA else 0 end) as PointsA,
       sum(case when B_Correct = 'Y' then PointsB else 0 end) as PointsB,
       (sum(case when A_Correct = 'Y' then PointsA else 0 end) +
        sum(case when B_Correct = 'Y' then PointsB else 0 end)
       ) as TotalPoints
from results
where weekId < 10
group by userId, weekID;

我不知道limit在查询中应该做什么，也不知道DISTINCT。如果您只想选择一个用户，请在where之前添加group by子句。

Answer 2

SELECT userID
, weekID
, SUM(case when A_Correct = 'Y' then pointsA else 0 end) 
+ SUM(case when B_Correct = 'Y' then pointsB else 0 end) 
as TotalPoints
FROM Results 
WHERE userID = 1
and weekID < 10
GROUP BY weekID 
ORDER BY weekID ASC;

用户按周而不是总计运行

2 个答案: