Question

我在这段代码中打开我的文本文件时遇到了麻烦。我这样做是正确的吗？本周刚刚开始使用C ++。

我现在正在写输出文件时遇到麻烦。我得到的唯一输出就是这个。 libc ++ abi.dylib：以std :: invalid_argument类型的未捕获异常终止：stoi：无转换（lldb）

先谢谢你们。

这是我的employeesIn.txt

<123>,<John>,<Brown>,<125 Prarie Street>,<Staunton>,<IL>,<62088>
<124>,<Matt>,<Larson>,<126 Hudson Road>,<Edwardsville>,<IL>,<62025>
<125>,<Joe>,<Baratta>,<1542 Elizabeth Road>,<Highland>,<IL>,<62088>
<126>,<Kristin>,<Killebrew>,<123 Prewitt Drive>,<Alton>,<IL>,<62026>
<127>,<Tyrone>,<Meyer>,<street>,<999 Orchard Lane>,<Livingston>,<62088>

这是我的代码

#include <iostream>
#include <string>
#include <fstream>

using namespace std;

struct Person {
string first;
string last;

};

struct Address {
string street;
string city;
string state;
string zipcode;
};

struct Employee {
Person name;
Address homeAddress;
int eid;
};

void readEmployee(istream& in, Employee& e);
void displayEmployee(ostream& out, const Employee& e);

int main(int argc, const char * argv[])
{
Employee e[50];

ifstream fin;
ofstream fout;

fin.open("employeesIn.txt");

if (!fin.is_open()) {
    cerr << "Error opening employeesIn.txt for reading." << endl;
    exit(1);
}
fout.open("employeesOut.txt");
if (!fout.is_open()) {
    cerr << "Error opening employeesOut.txt for writing." << endl;
    exit(1);
}
int EmployeePopulation = 0;
readEmployee(fin, e[EmployeePopulation]);
while (!fin.eof()) {
    EmployeePopulation++;
    readEmployee(fin, e[EmployeePopulation]);
}
fin.close();
for (int i = 0; i <= EmployeePopulation - 1; i++) {
    displayEmployee(fout, e[i]);
}

fout.close();

cout << endl;

return 0;
}

void readEmployee(istream& in, Employee& e)
{
string eidText;
if ( getline(in, eidText, ',') ) {
    e.eid = stoi(eidText);

    getline(in, e.name.first, ',');
    getline(in, e.name.last, ',');

    getline(in, e.homeAddress.street, ',');
    getline(in, e.homeAddress.city, ',');
    getline(in, e.homeAddress.state, ',');

    string zipcodeText;
    getline(in, zipcodeText, ',');
    e.homeAddress.zipcode = stoi(zipcodeText);
}


}
void displayEmployee(ostream& out, const Employee& e)
{
out << "Customer Record: " << e.eid
<< endl
<< "Name: " << e.name.first << " " << e.name.last
<< endl
<< "Home address: " << e.homeAddress.street
<< endl
<< e.homeAddress.city << ", " << e.homeAddress.state << " " << e.homeAddress.zipcode
<< endl
<< endl
<< endl;
}

Answer 1

正是它所说的：stoi失败了。

您只有两次，所以很明显您的eidText不是数字，或者您的邮政编码不是数字。

我们不知道这是由于输入文件的问题还是解析问题，因此在eidText之前将zipcodeText和stoi输出到控制台，你可以看到他们的价值观，然后继续相应的诊断。

从输入文件写入输出文件

1 个答案: