我有一个
class Player
{
public Vector3 position;
public String name;
}
和
class Field
{
public Vector3 position;
public bool isTarget;
}
我有一个有3个玩家,10个领域和3个目标领域的游戏。对于获胜,用户应将所有玩家放在目标字段上。有没有比较好的方法来比较2个不同的对象列表(List< Player>和List< Field>)但是具有相同的字段(位置)?
或者我应该从
继承Player和Fieldclass BaseItem
{
public Vector3 position;
}
class Player : BaseItem
{
public String name;
}
并比较List<BaseItem>
?
编辑:只是添加一些澄清:我有一个列表&lt;播放器&GT;和列表&lt;字段&GT;我想检查所有玩家是否与所有isTarget字段具有相同的位置。订单并不重要。
var listPlayer = new List<Player>();
listPlayer.Add(new Player { position = new Vector3(1,0,0); name = "a"; }
listPlayer.Add(new Player { position = new Vector3(0,1,0); name = "b"; }
listPlayer.Add(new Player { position = new Vector3(0,0,1); name = "c"; }
var listFields = new List<Field>();
listFields.Add(new Field { position = new Vector3(1,0,0); isTarget = true;}
listFields.Add(new Field { position = new Vector3(0,1,0); isTarget = true;}
listFields.Add(new Field { position = new Vector3(0,0,1); isTarget = true;}
listFields.Add(new Field { position = new Vector3(1,1,0); }
listFields.Add(new Field { position = new Vector3(1,0,1); }
****
我怎样才能浏览所有玩家和领域并看看,如果每个玩家都有一个相应的领域(它应该有相同的位置且isTarget应该是真的)?
解决方案:我想将Aybe的答案作为解决方案,但我已经完成了algorytm,所以我想分享它以防它有用:
private void CheckIfWin()
{
foreach (var target in gameboardTargets)
if (!IsAnyPlayerOnTarget(target))
return;
MessageBox.Show(HandleMessage,"You made it!", "Hooray!", MessageBoxButtons.OK);
}
private bool IsAnyPlayerOnTarget(Field target)
{
foreach (var player in playersList)
if (target.GridPosition.Equals(player.GridPosition)) // can be replaced with BaseItem.ComparePosition()
return true;
return false;
}
答案 0 :(得分:0)
不确定比较两种不同的方法是否正确。
但是,您可以将这两个内容派生自基类:
internal class BoardEntity {
public Vector3 Position { get; set; }
}
internal class Player : BoardEntity {
public string Name { get; set; }
}
internal class Field : BoardEntity {
public bool IsTarget { get; set; }
}
现在还有其他事情出现了:
floats
,因为结果可能会wrong 代码:
internal class BoardEntity {
public Vector3 Position { get; set; }
protected bool Equals(BoardEntity other) {
return Position.Equals(other.Position);
}
public override bool Equals(object obj) {
if (ReferenceEquals(null, obj)) return false;
if (ReferenceEquals(this, obj)) return true;
var other = obj as BoardEntity;
return other != null && Equals(other);
}
public override int GetHashCode() {
return Position.GetHashCode();
}
}
internal class MyClass {
public MyClass() {
var player = new Player();
var field = new Field();
BoardEntity boardEntity1 = player;
BoardEntity boardEntity2 = field;
bool b = boardEntity1.Equals(boardEntity2);
}
}
<强>建议:强>
提供ComparePosition()
方法听起来更自然IMO,因为我们转换为整数,所以比较总是正确的。
internal class BoardEntity {
public Vector3 Position { get; set; }
public bool ComparePosition(BoardEntity boardEntity) {
var v1 = new Vector3(boardEntity.Position.X, boardEntity.Position.Y, boardEntity.Position.Z);
var v2 = new Vector3(Position.X, Position.Y, Position.Z);
return v1.Equals(v2);
}
}
internal class MyClass {
public MyClass() {
var player = new Player();
var field = new Field();
bool comparePosition = player.ComparePosition(field);
}
}