Question

看看这个：

set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit

set policy id 1508

exit

set policy id 1507 from "CMS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit

set policy id 1507

set service "TCP-37"

exit

我想在退出Python列表之前设置整行，这意味着：

    list=[
'set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit\n\nset policy id 1508',
'set policy id 1507 from "CMS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit\n\nset policy id 1507\n\nset service "TCP-37"'
]

如何使用正则表达式执行此操作？

请注意，我希望在退出其中一个列表索引之前使用整个代码。我的意思是：

    list=[
'set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit\n\nset policy id 1508',
'set policy id 1507 from "CMS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit\n\nset policy id 1507\n\nset service "TCP-37"'
]

不是这个：

list=[
'set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit',
'set policy id 1508',
'set policy id 1507 from "CMS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit',
'set policy id 1507',
'set service "TCP-37"'
]

我想要

re.findall()

用于查找由set启动并以exit结束的字符串的模式。

罐中。

Answer 1

我们认为文本位于一个名为text的变量中。您可以使用str类的split方法（https://docs.python.org/2/library/stdtypes.html#str.split）。在Python解释器中：

>>> t = """set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit
...
... set policy id 1508
...
... exit
...
... set policy id 1507 from "CMS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit
...
... set policy id 1507
...
... set service "TCP-37"
...
... exit"""
>>> t.split("exit")
['set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit\n\nset policy id 1508\n\n', '\n\nset policy id 1507 from "C
MS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit\n\nset policy id 1507\n\nset service "TCP-37"\n\n', '']

如果要避免列表中的最后一个空元素，可以使用＆＃34; exit \ n＆＃34;来调用split方法。您还可以在列表的每个项目上调用strip方法，以删除每个元素开头和结尾的空格（这将为您提供预期的输出）。

Answer 2

s="""
set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit

set policy id 1508

exit

set policy id 1507 from "CMS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit

set policy id 1507

set service "TCP-37"

exit
"""
import re
re.findall('(set.*?)^exit',s,re.DOTALL|re.MULTILINE)


['set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit\n\nset policy id 1508\n\n', 'set policy id 1507 from "CMS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit\n\nset policy id 1507\n\nset service "TCP-37"\n\n']

如果你想要所有这些都是单行：

In [2]: import re   
In [3]: lines  = re.findall('(set.*?)^exit',s, re.DOTALL | re.MULTILINE)
In [4]: joined =  [" ".join(x.split()) for x in lines]    
In [5]: joined[0]
Out[5]: 'set policy id 1508 from "TEST" to "OPR" exit "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit set policy id 1508'    
In [6]: joined[1]
Out[6]: 'set policy id 1507 from "CMS-SrvFarm" to "DMZ" "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit set policy id 1507 set service "TCP-37"'

Answer 3

您可以尝试使用以下代码，该代码使用负前瞻和（DOTALL修饰符），

>>> import re
>>> s = """set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit
... 
... set policy id 1508
... 
... exit
... 
... set policy id 1507 from "CMS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit
... 
... set policy id 1507
... 
... set service "TCP-37"
... 
... exit"""
>>> m = re.findall(r'set(?:(?!exit).)*', s, re.DOTALL)
>>> m
['set policy id 1508 from "TEST" to "OPR"  "10.2.197.3/32" "ARG-VCENTER-SRV-1" "ANY" permit\n\nset policy id 1508\n\n', 'set policy id 1507 from "CMS-SrvFarm" to "DMZ"  "CMS-SRV5(10.2.90.14)" "THR-CMS-SRV-0" "TCP-123" permit\n\nset policy id 1507\n\nset service "TCP-37"\n\n']

获取开始和结束单词之间的所有内容

3 个答案: