Question

如何在几天内获得两个时间戳之间的差异？我应该使用datetime列吗？

<小时/> 我将我的专栏改为日期时间。简单的减法似乎不会在几天内给我一个结果。

mysql> SELECT NOW(), last_confirmation_attempt, NOW() - last_confirmation_attempt AS diff  FROM DateClubs HAVING diff IS NOT NULL ;
+---------------------+---------------------------+-----------------+
| NOW()               | last_confirmation_attempt | diff            |
+---------------------+---------------------------+-----------------+
| 2010-03-30 10:52:31 | 2010-03-16 10:41:47       | 14001084.000000 |
+---------------------+---------------------------+-----------------+
1 row in set (0.00 sec)

我不认为diff是在几秒钟内，因为当我将diff除以一天中的秒数（86,400）时，我得不到一个明智的答案：

mysql> SELECT NOW(), last_confirmation_attempt, ( NOW() - last_confirmation_attempt) / 86400 AS diff  FROM DateClubs HAVING diff IS NOT NULL ;
+---------------------+---------------------------+----------------+
| NOW()               | last_confirmation_attempt | diff           |
+---------------------+---------------------------+----------------+
| 2010-03-30 10:58:58 | 2010-03-16 10:41:47       | 162.0568402778 |
+---------------------+---------------------------+----------------+
1 row in set (0.00 sec)

Answer 1

如果您乐意忽略列中的时间部分，DATEDIFF()会在几天内为您提供所需的差异。

SELECT DATEDIFF('2010-10-08 18:23:13', '2010-09-21 21:40:36') AS days;
+------+
| days |
+------+
|   17 |
+------+

Answer 2

我知道已经很老了，但我只是为了它而说 - 我正在寻找同样的问题而且到了这里，但我需要在几天之内的差异。

我使用了SELECT (UNIX_TIMESTAMP(DATE1) - UNIX_TIMESTAMP(DATE2))/60/60/24 Unix_timestamp以秒为单位返回差异，然后我将其分为分钟（秒/ 60），小时（分钟/ 60），天（小时/ 24）。

Answer 3

CREATE TABLE t (d1 timestamp, d2 timestamp);

INSERT INTO t VALUES ('2010-03-11 12:00:00', '2010-03-30 05:00:00');
INSERT INTO t VALUES ('2010-03-11 12:00:00', '2010-03-30 13:00:00');
INSERT INTO t VALUES ('2010-03-11 00:00:00', '2010-03-30 13:00:00');
INSERT INTO t VALUES ('2010-03-10 12:00:00', '2010-03-30 13:00:00');
INSERT INTO t VALUES ('2010-03-10 12:00:00', '2010-04-01 13:00:00');

SELECT d2, d1, DATEDIFF(d2, d1) AS diff FROM t;

+---------------------+---------------------+------+
| d2                  | d1                  | diff |
+---------------------+---------------------+------+
| 2010-03-30 05:00:00 | 2010-03-11 12:00:00 |   19 |
| 2010-03-30 13:00:00 | 2010-03-11 12:00:00 |   19 |
| 2010-03-30 13:00:00 | 2010-03-11 00:00:00 |   19 |
| 2010-03-30 13:00:00 | 2010-03-10 12:00:00 |   20 |
| 2010-04-01 13:00:00 | 2010-03-10 12:00:00 |   22 |
+---------------------+---------------------+------+
5 rows in set (0.00 sec)

Answer 4

如果您想以完整的TIMESTAMP格式返回，请尝试： -

 SELECT TIMEDIFF(`call_end_time`, `call_start_time`) as diff from tablename;

返回

     diff
     - - -
    00:05:15

Answer 5

如果您需要在几天内计算差异，那么

<% if (window.x !== undefined && window.x !== null) { %>
  <div> Foo </div>
<% } %>

它将返回
SELECT TIMESTAMPDIFF(SECOND,'2010-09-21 21:40:36','2010-10-08 18:23:13')/86400 AS diff
diff

Answer 6

SELECT DATEDIFF( now(), '2013-06-20' );

这里，datediff有两个参数'upto-date'，'from-date'

我所做的是，使用now（）函数，我可以得到否。自2013年6月20日至今的几天。

Answer 7

选择DATEDIFF（max_date，min_date）作为我桌子的天数。即使col max_date和min_date位于字符串数据类型中，此方法仍然有效。

两天的两个时间戳之间的MySql差异？

7 个答案: