Question

有人可以在此代码中发现任何明显错误吗？该网站没有加载所以我猜这个问题是在PHP的某个地方。该网站是空白的，您可以找到问题所在的任何信息。这只是一小段代码，但它是包含php的唯一一段代码。

<?php

ini_set('display_errors', 'on');

$dir = "sound";
$bucketsArrayString = "var buckets = [";
if (is_dir($dir))
{
  $bucket = "";
  $intensity = "";
  $position = "";
  $distance = "";

  echo "var soundTree = \n[";

  if ($dh = opendir($dir))
  {
    for($i = 0; ($file = readdir($dh)) !== false; )
    {
      if($file[0] != ".")
      {
        if($i > 0)
        {
          echo ",";
          $bucketsArrayString .= ", ";
        }
        echo "\n\t[";

            $bucketsArrayString .= "'$file'";
        $bucket = $file;

        $distances = array("close", "medium", "distant");
        for($j = 0; $j < count($distances); $j++)
        {
          if($j > 0)
            echo ",";
          echo "\n\t\t[";

          $distance = $distances[$j];

          $positions = array("back", "front", "left", "right");
          for($k = 0; $k < count($positions); $k++)
          {
            $position = $positions[$k];

            if($k > 0)
              echo ',';
            echo "\n\t\t\t[";           

                $intensities = array("often", "seldom");
                for($l = 0; $l < count($intensities); $l++)
                {
                $intensity = $intensities[$l];

                $folder = $dir . "/" . $bucket . "/" . $distance . "/" . $position . "/" . $intensity;
                if($l > 0)
                  echo ',';
                echo "\n\t\t\t\t[";

                $m = 0;

                if ($dirHandle = opendir($folder))
                {
                while (($fileHandle = readdir($dirHandle)) !== false)
                {

                if($fileHandle[0] != ".")
                {
                  if($m > 0)
                    echo ",";
                  echo "\n\t\t\t\t\t'" . $fileHandle . "'";
                  $m++;
                }
              }
              echo "\n\t\t\t\t]"
            }
            echo "\n\t\t\t]";
          }
          echo "\n\t\t]";
        }
        echo "\n\t]";
        $i++;
      }
    }
    closedir($dh);
    $bucketsArrayString .= '];';
  }

  echo "\n];\n";
}

echo $bucketsArrayString;
?>

Answer 1

您应该使用：

error_reporting(E_ALL);
ini_set('display_errors', 1);

而不是：

ini_set('display_errors', 'on');

Answer 2

将第75行更改为此

 echo "\n\t\t\t\t]";       // missing semicolon

并在末尾添加}

echo $bucketsArrayString;
}                          // missing bracket
?>

Answer 3

试 error_reporting(E_ALL); ini_set('display_errors', 1); 而不是

ini_set('display_errors', 'on');

然后您将收到所有错误和警告

无法在php中找到错误

3 个答案: