我在尝试使用以下XML代码时遇到问题。首先,例外是<items xmlns=''> was not expected.
,我似乎已经能够通过指定XmlRootAttribute
来解决这个问题。现在,它回来了一个空的List<Items>
,我无法弄清楚为什么。有什么想法吗?
<?xml version="1.0"?>
<items>
<item>
<version>1.0</version>
<title>Example</title>
<changelog>http://example.com/changelog.txt</changelog>
<url>http://www.example.com/download/</url>
</item>
</items>
Stream appCastStream = webResponse.GetResponseStream();
UpdateXML updateXml = new UpdateXML();
var rootAttribute = new XmlRootAttribute();
rootAttribute.ElementName = "items";
rootAttribute.IsNullable = true;
XmlSerializer serializer = new XmlSerializer(typeof(UpdateXML), rootAttribute);
try
{
using (XmlTextReader reader = new XmlTextReader(appCastStream))
{
if (serializer.CanDeserialize(reader))
{
updateXml = (UpdateXML)serializer.Deserialize(reader);
}
else
{
throw new Exception("Update file is in the wrong format.");
}
}
}
catch (Exception ex)
{
Debug.WriteLine("The following error occurred trying to check for updates: {0}", new object[] { ex.Message });
return;
}
public class UpdateXML
{
public class Item
{
private string _versionString;
private string _title;
private string _changelog;
private string _url;
[XmlElement("version")]
public string VersionString
{
get { return this._versionString; }
set { this._versionString = value; }
}
public Version Version
{
get
{
if (string.IsNullOrEmpty(this._versionString))
return null;
return new Version(this._versionString);
}
}
[XmlElement("title")]
public string Title
{
get { return this._title; }
set { this._title = value; }
}
[XmlElement("changelog")]
public string ChangeLog
{
get { return this._changelog; }
set { this._changelog = value; }
}
[XmlElement("url")]
public string URL
{
get { return this._url; }
set { this._url = value; }
}
}
private List<Item> _items = new List<Item>();
[XmlArray("items")]
[XmlArrayItem("item")]
public List<Item> Items
{
get { return this._items; }
set { this._items = value; }
}
public UpdateXML()
{
}
}
答案 0 :(得分:1)
我认为问题在于你的XML确实没有&#34; root&#34; element--顶级元素是一个数组。 This answer应用于您的问题似乎解决了问题(同时删除了传递给rootAttribute
的{{1}}参数):
XmlSerializer
示例: https://dotnetfiddle.net/MAet5y
如果您能够修改XML,则可以添加根元素,这样也可以解决问题。
例如,如果您将当前XML包装在[XmlRootAttribute("items")]
public class UpdateXML
{
private List<Item> _items;
[XmlElement("item")]
public List<Item> Items
{
get { return this._items; }
set { this._items = value; }
}
}
中,然后按如下方式修改<root></root>
类:
UpdateXML