Submitted.html JS也被document.ready函数
包围var uploader = new qq.FileUploader({
action: "{% url 'QCOMLTE:imager' %}",
element: $('#file-uploader')[0],
multiple: true,
onComplete: function(id, fileName, responseJSON) {
if(responseJSON.success) {
alert("success!");
} else {
alert("upload failed!");
}
},
onAllComplete: function(uploads) {
// uploads is an array of maps
// the maps look like this: {file: FileObject, response: JSONServerResponse}
alert("All complete!");
},
params: {
'csrf_token': "{{ csrf_token }}",
'csrf_name': 'csrfmiddlewaretoken',
'csrf_xname': 'X-CSRFToken'
}
});
html body中的其他地方
<div id="file-uploader">
<noscript>
<p>Please enable JavaScript to use file uploader.</p>
</noscript>
</div>
urls.py
urlpatterns = patterns('',
url(r"^Submitted/$", views.HybridDetailView.as_view(), name='Submitted'),
url(r'^(?P<object_type>\w+)/process/$', views.process, name='process'),
url(r'^(?P<object_type>\w+)/$', views.generic_view, name='generic'),
url("$^", views.head, name='head'),
url("uploader", views.upload, name= 'imager'),
)
views.py
@AjaxFileUploader
def upload(request):
response = {'files': []}
script_dir = os.path.dirname(__file__)
# Loop through our files in the files list uploaded
print('request',request)
print(request.FILES)
for item in request.FILES.getlist('files[]'):
file = UploadedFile(item)
with open(script_dir + '/Excel/' + file.name) as destination:
for chunk in file.chunks():
destination.write(chunk)
response['files'].append(file)
print('appended')
return HttpResponse(json.dumps(response), content_type='application/json')
还在已安装的应用列表中包含“ajaxuploader”
当我尝试通过按钮提交文件时,它会发送帖子调用但收到400(BAD REQUEST)错误。 它甚至没有从我所知道的到达python,至少不是视图代码。它似乎正确地形成了请求URL
http://localhost:8000/QCOMLTE/uploader?qqfile=powered_by.png
当您转到该URL时,它会发送一条消息,指出仅允许发布呼叫。 这类似于Default django-ajax-uploader with s3 backend gives MalformedXML error 除了我没有使用任何后端,只是尝试抓取文件并将它们保存到目录。
更新8/25/14: 从视图中删除了装饰器。这导致错误未被发送。打印请求后,很明显文件正在发送到GET路径而不是FILE路径。我不知道如何改变这一点。
答案 0 :(得分:0)
找到此Need a minimal Django file upload example
后我之前尝试模仿它,发现FILE和POST请求实际上正在通过,不像我正在使用的ajax / jquery。 JQuery是
$('#uploadform').submit(function (e){
console.log('submitting')
var data = new FormData($('#uploadform').get(0));
$.ajax({
type: 'POST',
url: "{% url 'QCOMLTE:imager' %}",
data: data,
success: function(data){console.log(data)},
error: function(data){console.log(data)},
cache: false,
processData: false,
contentType: false
});
e.preventDefault()
});
除了类型低于URL。 我尝试将其更改为$ .post请求,并且它尝试发布到错误的网址然后... 所以我决定改回来,这次把类型放在ajax调用的顶部。然后它工作了......经过多次测试后仍然可以。