Question

我正在开发一个Adobe Echosign演示C＃winforms应用程序。我的代码是他们的命令行代码的直接副本（有修改），但是，我的代码在传输数据后返回错误。

这是EchoSign的命令行代码

public static void sendDocument(string apiKey, string fileName, string formFieldLayerTemplateKey, string recipient)
{
    FileStream file = getTestPdfFile(fileName);
    secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
    fileInfos[0] = new secure.echosign.com.FileInfo(fileName, null, file);
    SenderInfo senderInfo = null;
    string[] recipients = new string[1];
    recipients[0] = recipient;
    DocumentCreationInfo documentInfo = new DocumentCreationInfo(
        recipients,
        testPrefix + Path.GetFileName(file.Name),
        testMessage,
        fileInfos,
        SignatureType.ESIGN,
        SignatureFlow.SENDER_SIGNATURE_NOT_REQUIRED
    );
    if (formFieldLayerTemplateKey != null)
    {
        secure.echosign.com.FileInfo[] formFieldLayerTemplates = new secure.echosign.com.FileInfo[1];
        formFieldLayerTemplates[0] = new secure.echosign.com.FileInfo(formFieldLayerTemplateKey);
        documentInfo.formFieldLayerTemplates = formFieldLayerTemplates;
    }
    DocumentKey[] documentKeys;
    documentKeys = ES.sendDocument(apiKey, senderInfo, documentInfo);
    Console.WriteLine("Document key is: " + documentKeys[0].documentKey);
}

这是我的代码块，它从系统返回错误：

public static void sendDocument(string apiKey, string fileName, string formFieldLayerTemplateKey, string recipient)
{
    try
    {
        SenderInfo senderInfo = new SenderInfo();
        senderInfo = null;

        FileStream FileToSign = getTestPdfFile(fileName);
        byte[] bytes = System.IO.File.ReadAllBytes("C:\\PROJECTS\\TestFile.pdf");


        secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
        fileInfos[0] = new EchoSignTest.secure.echosign.com.FileInfo();
        fileInfos[0].fileName = fileName;
        fileInfos[0].mimeType = null;
        fileInfos[0].file = bytes;

        RecipientInfo[] docRecipient = new RecipientInfo[1];
        docRecipient[0] = new RecipientInfo();
        docRecipient[0].email = recipient;

        DocumentCreationInfo documentInfo = new DocumentCreationInfo();
        documentInfo.recipients = docRecipient;
        documentInfo.name = testPrefix + Path.GetFileName(FileToSign.Name);
        documentInfo.message = testMessage;
        documentInfo.fileInfos = fileInfos;
        documentInfo.signatureType = SignatureType.ESIGN;
        documentInfo.signatureFlow = SignatureFlow.SENDER_SIGNATURE_NOT_REQUIRED;

        if (formFieldLayerTemplateKey != null)
        {
            secure.echosign.com.FileInfo[] formFieldLayerTemplates = new secure.echosign.com.FileInfo[1];

            formFieldLayerTemplates[0] = new secure.echosign.com.FileInfo();
            formFieldLayerTemplates[0].formKey = formFieldLayerTemplateKey;
            documentInfo.formFieldLayerTemplates = formFieldLayerTemplates;
        }

        EchoSignDocumentService19PortTypeClient ES = new EchoSignDocumentService19PortTypeClient();
        DocumentKey[] documentKeys = new DocumentKey[1];

        documentKeys = ES.sendDocument(apiKey, senderInfo, documentInfo);
        Console.WriteLine("Document key is: " + documentKeys[0].documentKey);
    }
    catch (NullReferenceException ex)
    {
        string errMessage = ex.Message;
    }

    catch (Exception ex)
    {
        string errMessage = ex.Message;
    }
}

两个代码块之间有什么不同？该错误可能位于FileInfo[]或DocumentCreationInfo()块中。我可能不是按系统要求创建对象。

任何建议都表示赞赏。

Answer 1

错误似乎是将您读取的文档的字节直接分配给fileInfos[0].file变量。在documentation for FileInfo中，它声明文件参数必须是原始文件内容，使用base64 进行编码，但您可以分配原始文件内容而不对其进行编码。当使用像第一个示例（命令行一样）中的文件流调用构造函数时，构造函数似乎会自动处理它。您可以尝试在Winforms示例中更改这些行：

    FileStream FileToSign = getTestPdfFile(fileName);
    byte[] bytes = System.IO.File.ReadAllBytes("C:\\PROJECTS\\TestFile.pdf");


    secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
    fileInfos[0] = new EchoSignTest.secure.echosign.com.FileInfo();
    fileInfos[0].fileName = fileName;
    fileInfos[0].mimeType = null;
    fileInfos[0].file = bytes;

进入此代码并尝试这是否有效：

    FileStream FileToSign = getTestPdfFile(fileName);


    secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
    fileInfos[0] = new secure.echosign.com.FileInfo(fileName, null, FileToSign);

您应该使用提供的构造函数而不是直接赋值来确保正确处理所有变量/参数。

你在关于不带3个参数的构造函数的注释中告诉你的错误可能是构造函数调用之前EchoSignTest.前缀的结果，因为它似乎是你自己的程序的命名空间而不是正确的提供的API的命名空间。

命令行c＃代码有效，但winforms代码没有

1 个答案: